Hi Buddy,

in 2019 ,closing rank in Shri Ramdeobaba college of engineering for CSE was 20269 and for IT was 38279 . And in 2018 closing score was 143 for CSE and 120 for IT.

To get rank in between 20k to 30k you should have percentile of about 97.

Hello Aspirant,

See there is no any minimum percentile required to be eligible for admission in NITs for any category because the seat allotment process is based on the rank of candidate but if you are General candidate and wants to get into top 5 NITs with CSE/IT branch then

Hello,

Based on the previous year cut off trends here is the list of institutes in which you may have chances of getting seat in IIT, Kanpur in M.Tech Computer Science. the cut off for OBC category was 349. It is difficult to get seat in IITs and NITs with

GATE CSE becomes more tough not only due to the vaste Syllabus, but due to the High Competition across India. A strong test taking strategy as well as a Good and regular Test Series are highly required, provided you are done with the Preparation and Syllabus Revision. Nowadays, besides offline,

Hello Aspirant,

According to the mentioned percentile your rank is expected to be in the range of 294419 - 330970 , you can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

Hello Aspirant,

If we go through the analysis of previous year's GATE score Vs College allotment than according to the GATE 2021 score mentioned by you in the query, you have chances in following colleges :-

NIT Trichy

NIT Calicut

And some more. You can check out previous year's cut-offs

Hello,

If you're looking for top Engineering Institutions offering B.Tech in Computer Science and Engineering then you don't need to look out for other Institutions than IITs. Here's the top IITs for this course-

1. Indian Institute of Technology, Madras

2. Indian Institute of Technology, Delhi

3. Indian Institute of

Hello Aspirant,

If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2020 then according to the percentile mentioned by you in the question your rank is expected to be in the range of 81840 - 92000 , you can check out marks Vs ranks Vs

Hello Dear,

Common Admission Test (CAT) is a computer-based test. In the question paper of CAT questions are included from 3 sections that are Verbal Ability and Reading Comprehension, Data Interpretation and Logical Reasoning and Quantitative Ability. The question papers of CAT provide you with a clear picture of CAT