Computer Science Engineering
TIET has introduced the revised eligibility criteria from this year due to this global pandemic. Please reach out at the below link for more information:
https://admissions.thapar.edu/Prospects/files/Revised_criteria_and_Schedule_for_BE-BTech_First_year_Admissions_.pdf
Hope this will help you!!
Hello ,
it is hard to predict as cutoff for current depends on the average performance of candidates, seat matrix and demand of the respective branch.
Here are some college names where you have possibility to get CSE or ISE:-
hey manjunath,
please mention the college and examination regarding your question, so that we can answer and solve your query. your information is incomplete.
Hi Amod Kumar,
As per your rank and as per previous year cutoff, the colleges you will get in Computer Science and Engineering are:-
NIT SURATHKAL CUTOFF FOR OBC IN COMPUTER SCIENCE AND ENGINEERING:
2019 - 2627 (home state), 627 (other state)
2018 - 2237 (home state), 663 (other state)
2017 - 3723( home state) , 950 ( other state)
2016 - 2515 (home state), 411 (other state)
For more information related to cutoff
Hello aspirant,
I would suggest you to go with IIT Hyderabad because it is a recognized institution , I agree even NIT is but the advantage of joining IIIT Hyderabad is a dual degree is better than a normal degree because it helps the student to complete 2 degrees in
Hi Aspirant,
As per your rank and as per previous year cutoff, you will get The National Institute of Engineering in B.E. in Computer Science and Engineering.
The last cutoff rank for The National Institute of Engineering in B.E. in Computer Science and Engineering goes till 21000. So, you will
Generally cutoffs changes every year it depends upon various factors like, difficulty level of the entrance exam, number of students applying for the exam, performance of the students in the exam, etc.
But in general if you consider previous year cutoffs then you can easily get CSE in Reva as
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