Hello,

Using our JEE Main Rank Predictor tool with 200 marks your rank will be in between  1854-3504. In 2019 a candidate belonging to general category (Andhra Pradesh) with rank 2328 secured seat in NIT, Warangal in CSE and candidate under home state quota with rank 2977 secured seat in

Hi aradhya,

Delhi University is a central university offering many undergraduate courses in Science. The cut off varies for every science course depending on the college. Following are few science course offered in Delhi University:

• B.Sc. (Genl) Mathematical Science
• B.Sc. (Hons.) Instrumentation
• B.Sc. (Hons) Anthropology
• B.Sc. (Hons) Bio-Chemistry
• B.Sc. (Hons)

Hello,

In engineering fields the PCM marks of boards is not a big deal. Minimum of 75% board marks  is required in maximum state college and some colleges also prefer less than 75% i.e 40% to 50%. So this is not the main point.

As per the previous years cut

Dear aspirant,

The Saranathan college was established in year 1998 where the infrastructure is really good and almost 75% people pursuing CSE got placed in top companies with packages of around 17 lac per annum.

The total  fees here for 4 year CSE course is 2 lacs .

While the

Hello aspirant

You have got good PCM score and average Jee main score. There has been very tough competition for CS branch in all colleges. You will get BE seat in Thapar University but about CS branch can't say.

It depends on cut off of of jee main 2020 and

Hey,

You have to meet various parameters to be eligible for the cse branch of Sastra university.

You can check the below link for more details:

https://engineering.careers360.com/articles/sastra-university-btech-eligibility-criteria

Hello!!!

Hope you are doing great!!!!

For getting seat in top 5 NIT's for a general category students,All India rank should be around 1000-5000 approximately.And the percentile should be around 98-99 percentile.You can check the previous year's cutoff for top NIT's in the link provided below:

https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits

Hope it helps!!!

Hello!!!!

Hope you are doing great!!!!

Given mass of the rod = m

length of the rod= l

Potential energy is present at the center of the rod.So the length should be taken from the center to one of the edge of the rod,i.e l= l/2

As the angle is

Dear Nikita,

Congratulations for qualifying the 12th exam with good marks.

Delhi university is one of the top colleges of India. There are several colleges in the Delhi university which comes in the top colleges of the country. There are several courses offered in the colleges of Delhi university. Delhi