Correct Answer: TASTE

Solution : Given:
ERADICATE

Let's compare all the option words with the word ERADICATE –
First option: AREA; All the letters of AREA are present in the word ERADICATE.
Second option: CARE; All the letters of CARE are present in the word ERADICATE.
Third option: DICE; All

Correct Answer: IMWGTC

Solution : Given:
ZEPHYR is coded as IIYLHV and SCHIZY is coded as BGQMIC.

Add 9 to the positional value of the odd place letter and add 4 to the positional value of the even place letter to obtain the required code –
Z + 9 =

Correct Answer: 40 cm

Solution :
The perpendicular from the centre of a circle to a chord bisects the chord.
By Pythagoras theorem:
Hypotenuse² = Base² + Perpendicular²
MP = PN = $\frac{\text{MN}}{2}$ = $\frac{48}{2}$ = 24 cm
Distance from the centre as $d_{1}$ = 15 cm

Correct Answer: Vani Jairam

Solution : The Correct Option is Vani Jairam

Vani Jairam was named the recipient of the 2020 "M.S. Subbulakshmi Award" by the Tamil Nadu Eyal Isai Nataka Manram. This honor, which bears the name of the renowned Indian classical vocalist M.S. Subbulakshmi, is given to people

Hello aspirant,

I regret to inform you that a B.Sc. in computer science at DU requires a math component.

The requirements for eligibility include a minimum of 60% in maths in your 12th grade year and the necessity to search for cutoffs in order to be admitted. Cut-offs are extremely

NO.

Most countries require a Bachelor’s degree (3–4 years) for MS in Computer Science.

What you should do first:

Complete B.E./ BTech in Computer Science / IT OR

Complete BSc . Computer Science / BCA (then sometimes MSc . before MS, depends on country)

After Bachelor’s, you can apply for

Correct Answer: 84

Solution : Given:
6 : 42 :: 12 : ?

Like, 6 × 7 = 42
Similarly, 12 × 7 = 84

So, 84 is the required answer. Hence, the fourth option is correct.

Hello aspirant,

Yes, since graduation is the minimal need, you are qualified to register for the CS Executive Programme after passing your final year of B.Com. Candidates who have finished their BCom coursework are eligible to enrol directly in the CS Executive programme.

Twice a year, the CS entrance exam

Correct Answer: 16

Solution :
In $\triangle AOS$, AO is the radius.
⇒ $AO = 10$ cm
It is right-angled at S,
Applying Pythagoras theorem, we get,
$AO^2=OS^2+AS^2$
⇒ $10^2=6^2+AS^2$
⇒ $100-36=AS^2$
⇒ $AS^2 = 64$
⇒ $AS=8 $ cm
Now, $AS = \frac{1}{2}×$ Length of the chord
⇒ Length