Hello,

You can attempt free mock test on COMEDK official website and the link for the same is given bellow

https://www.comedk.org/about-uget-and-notification/#ffs-tabbed-19

Go to the mock test section and click on it you will be able to see three mock tests you can attempt all of those three as per your

The COMEDK examination rescheduled to July 25 earlier the examination was to be conducted on 27 June. If you're preparing for Jee main July then you can continue your preparation just solve past few year papers of Comedk as the level of question is different in Jee main and comedk

Hi

No , your subject wise marks is not considered dear , your aggregate marks in your class 12th board examination is considered.

COMEDK UGET eligibility criteria says that, to be eligible  you must have pass your class 12th board examination with Physics, Chemistry and Mathematics and must have goat

The eligiblity criteria for the Sharda University is on merit based and should have min of 50% and should have Proficiency in English communication.

Hey there

COMEDK exam is strictly on 11th and 12th syllabus and it do covers almost complete 11th and 12th syllabus. there will be 180 questions and maximum time allowed is 3 hours wit questions from PCM. each question will be of 1 marks and exam will be computer based.

hi,

comedk uget exams has scheduled on 27 june, 2020. however till now no officials notifications available regarding further postponed of exams.

I suggest you to make your preparation going on and practices daily.

follow the official website as well as careers360 website to know upcoming details of exams.

Hello,

Consortium of Medical Engineering and Dental Colleges of Karnataka Under Graduate Entrance Test (COMEDK UGET) application last Date for Submission of Filled Application Form and Online Payment  was 30th May 2020. The registrations are closed now. Please click the below link to know more.

https://engineering.careers360.com/articles/comedk-uget

Hello!!!!

Hope you are doing great!!!!

Given mass of the rod = m

length of the rod= l

Potential energy is present at the center of the rod.So the length should be taken from the center to one of the edge of the rod,i.e l= l/2

As the angle is