• ICFAI Business School Hyderabad (6.2 lakhs)
• Amity University Noida (1.7 lakhs)
• SRM University (3 lakhs)
• Chandigarh University (1.6 lakhs)
• Ambedkar Institute of Management Studies (1.4 lakhs).

Hello Aspirant,

It would be difficult to get OBC rank however You may calculate your expected general rank by this formula

100 - your total percentile score is the percentage  of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100

Hello Aspirant

With this percentile in JEE MAINS PAPER 2,your expected rank should be 2478 and its a good chance for you that you will get some NITs and also it depends on your category,if you belong to reserved category,there are some chances that you will get top NITs. But

Hello

Admissions are open at Kalakshetra Foundation for full time four year diploma courses.
Applications are also invited for the post of PGT (Economics).
Check the detailed information from the official website:

https://www.kalakshetra.in/newsite/

If you are looking for any other post/course, do let us know.

Good Luck!

Hello dear student !

DCRUST university is located in murthal, Haryana (comes in Delhi-NCR region) and offer various courses for the students. It also provides hostel facilities. The fee structure of DCRUST murthal for B. Arch course in OBC category is INR 47,050 per annum.

Hope this will help you

Hello Aniruddha,

Congratulations on your performance!

According to our Rank Predictor your estimated rank is roughly around 16,834. It is really difficult to get anything substantial with such a percentile.

You should look for private colleges like SRM University and Amity University.

You can also look upto our college predictor

Hi  Binayak,

You got 98.89 percentile in JEE main exam, your rank would be approximately in between 1000 to 2000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your

Rajesh, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:

(100-your total percentile) x 112679/100

So with 93.8 percentile, your rank would be around 6986.

Most top colleges in India require a rank of 5000 or below in JEE Mains paper

Hello Mulange vishnu prasad,

you can predicate your rank by using the formula.,

(100-your percentile)*no.of students wrote the exam/100,for the january exam total no of students are 112679,by this you can find your rank.

Then you rank is to be 36301

And also rank will be changed after the April