Hey there!

Well, there's no precise answer to your question because whether you get into an NIT or not depends on your home state. For instance, if NIT Hamirpur falls under your home state you'll get a branch using home state quota. To see what all colleges you can get

What is registration number in application form

Hello student.

A rank of 17000 is a bit of a low score for you to fetch you a seat in amritha campus in open quota for computer science engineering. And the branch of computer science is a demanding one. Not just that branch, branches like electronics and communication engineering,

hi

KIITEE means Kalinga Institute of Industrial Technology Entrance Examination.

For 5100 rank you can get seat in following branches

Electronics and instrumentation engineering closing rank is 30415

Computer science engineering closing rank is 5044

Mechanical engineering closing rank is 11074

MEchanical engineering in automobile closing is 17450

Electrical engineering

Hello Aspirant,

As per the Cutoff of JEE mains SC category this year(2020) is 50.18 percentile and you have score quite good compare to it but to get selected in a NIT or IIIT you need to hold a good rank ,so looking at that, you might get a low

Hello Aspirant,

See your eligibility for JEE-Advance is not determined by your rank in JEE-Main instead it is determined by the percentile you scored in your JEE-Main final result. As we know that NTA released the cut-offs for different categories so it is also described below :-

• Common Rank List

Hello,

Candidates who are in top 2,50,000 can apply for JEE Advanced. As you have CRL 284784 you cannot apply for JEE Advanced however, you have still qualified for JEE Main the cut off percentile for JEE Main 2020 for OBC-NCL is 70.2435518. You are eligible to participate in JoSAA

Hi dear,

Cutoff of OBC-NCL students for appearing in jee advance is 72.888 percentile. If you have scored more than this you are eligible for jee advance if you have scored lesser than this you are not eligible. You can check cutoff here

https://www.google.com/url?sa=t&source=web&rct=j&url=https://engineering.careers360.com/articles/jee-main-cutoff/amp&ved=2ahUKEwi9v8iBkuTrAhUnwzgGHbSGC7kQFjAHegQIDhAK&usg=AOvVaw0ay0p7xaI0Sc82xeEH0ED5&ampcf=1

Hope it helps you.