Engineering and technology
Dear Mali,
Hey,
Shanmugha Arts, Science, Technology & Research Academy , popularly known as SASTRA University , is a deemed to be university in the town of Thirumalaisamudram. The university has a good placement for IT students with the highest salary package of INR 28 LPA in top recruiting companies
Hello Aspirant.
Probably it is harder for you to get in. Don’t expect too high. You might be knowing about the selection criteria. Two streams one purely based on (STREAM 2) intermediate board percentage and other on (STREAM 1)25% mains score+ 75% intermediate board percentage. If your rank falls below
Hello student cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination.
With this rank its difficult to get admission in CSE Branch as we all know that seats are very limited and admission is
Hello student we don't promote donation I request you to please help me with your preferable college so that I can check and provide you the exact information about academic fees.
There are some college where management quota are reserved in which you can get admission by paying more fees.
Hello!!
Hope you are doing great!!!
Sorry!!You did not specify the examination in which you want to know the cutoff.Kindly mention the name of the examination and the university/college for which you want to know.Then we can provide the answer for your query.
Hope it helps!!!
Hello Aspirant,
I'm sorry to inform you that you can not apply for BITSAT now. The last date to apply for BITSAT was 11th May, 2020. And the exam will be conducted from 6th to 10th August, 2020. For further information you can visit here.
https://www.bitsadmission.com/
hey,
can you help us with the college name are you enquiring about, you have mentioned any detail about it , without knowing colleges name it would be difficult for us to provide the information .
kindly mention the college name in the comment section given below.
Dear Aspirant,
To know the rank there is. a formula
According to the formula, your JEE rank for general category is (100- percentile) * 869010/100. So the rank is 102543. For OBC, it is 1/3 of the general rank
So the OBC rank is 34181
You can use the jee
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