Exam
To be eligible for NDA 1 in 2025 , you must be born in between 2nd July 2006 and 1st July 2009 . Since your date of birth is in between this , you can attempt the exam . Also , as long as you are a twelfth graduate and
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Question : Match the following:
Option 1: (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
Option 2: (a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
Option 3: (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
Option 4: (a) - (iii), (b) - (ii), (c) - (iv), (d) - (i)
Correct Answer: (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)
Solution : The correct answer is (a) - (ii), (b) - (iv), (c) - (i) and (d) - (iii).
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Question : Select the most appropriate option to improve the underlined segment in the given sentence. If there is no need to improve it, select ‘No improvement required’.
I have withdraw money from the bank.
Option 1: have withdrawing
Option 2: No improvement required
Option 3: have withdrew
Option 4: have withdrawn
Correct Answer: have withdrawn
Solution : The fourth option is the correct choice.
The sentence contains a verb-tense error. When forming the present perfect tense, the past participle of the verb should be used. The past participle of withdraw is withdrawn. The use of the present perfect tense suggests a
Question : If $\tan \theta \cdot \tan 2 \theta=1$, then the value of $\cot 5 \theta$ is:
Option 1: $-1$
Option 2: $1$
Option 3: $-\sqrt{3}$
Option 4: $\sqrt{3}$
Correct Answer: $-\sqrt{3}$
Solution : Given: $\tan \theta \cdot \tan 2 \theta=1$ $⇒\tan2\theta=\cot\theta$ $⇒\tan2\theta=\tan(90°- \theta)$ $⇒2\theta=90°- \theta$ $⇒3\theta=90°$ $\therefore \theta=30°$ $\cot 5\theta=\cot(5×30°)=\cot 150°=\cot(90°+60°)=-\tan60°=-\sqrt3$ Hence, the correct answer is $-\sqrt3$.
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