GCET B.Arch
Hello,
College intakes student on the basis of rank. Admission solely depends on the rank you have secured. You haven't mentioned your rank. At NIT campus the accept ranks below 2k in general category.
B Arch and B Planning has total marks of 400 in JEE main and your score
Hi dear,
You have scored 90.16 percentile in JEE main paper 2 that means your rank should be 11087. You can also calculate your rank as
Rank=(100-your percentile)×112679÷100
Since you belong from general category you have low chance to get any NIT. You should reappear in april month exam and
You have scored 98.89 percentile in JEE main paper 2 that means your rank should be around 1250. You can also calculate your rank as
With this rank you have a chance to get NITs. You can check your college here
https://www.google.co.in/url?q=https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning&sa=U&ved=2ahUKEwjD_emnj67nAhVd8XMBHduMBNUQFjADegQIBxAB&usg=AOvVaw0j_xG9vFSjdcJuR_mJttH0
Hope it helps.
Hello ,
For JEE mains paper 2 , you must get more than 75 percentile for having chance to get admission in any NITs . For particularly , NIT trichy click on the given link below to see the cut off last year so as to get idea about how
Hello!
To qualify for B.Arch in IIT Kharagpur you have to write both JEE Main and JEE Advanced.
Only Admission Seeker who have qualified the JEE Mains are allowed to sit for JEE Advanced. If a student wants to join B.Arch in IIT Kharagpur they first have to clear JEE
Vikas, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:
(100-your total percentile) x 112679/100
So with 97.69 percentile, your rank would be around 2602.
Also, if the number of students increases to 1.5 lakh in the April session, the formula
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