health
Hey Deena,
Hope you're doing great!!
So, you can easily find go through this link and download your CUET syllabus for MSc in Public Health.
https://university.careers360.com/articles/cuet-pg-syllabus
You can also go through thre question papers to get a good overview of the entrance exam.
Hope this helps you.
Question : If $\sin ^2 \theta-3 \sin \theta+2=0$, then find the value of $\theta\left(0^{\circ} \leq \theta \leq 90^{\circ}\right)$.
Option 1: 45°
Option 2: 0°
Option 3: 60°
Option 4: 90°
Correct Answer: 90°
Solution : Given, $\sin ^2 \theta-3 \sin \theta+2=0$ ⇒ $(\sin \theta - 1)(\sin \theta- 2)=0$ ⇒ $\sin\theta=1$ or $\sin\theta=2$ Since $\left(0^{\circ} \leq \theta \leq 90^{\circ}\right)$, ⇒ $\sin \theta=1$ ⇒ $\theta = 90^{\circ}$ Hence, the correct answer is $90^{\circ}$.
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