Hello,

Indian Institute of Food Processing Technology, Thanjavur will conduct IIFPT Admission 2020 for allotment into B.Tech (Food Technology) course. The application process of IIFPT admission 2020 will commence tentatively from the third week of May. In order to complete the application form of IIFPT admission 2020, candidates will have

Chandru, since the passing percentage of JEE Mains 2020 is 75% (65% for SC/ST/PWD candidates) and only the candidates who passed JEE Mains 2020 is eligible for admission in IIFPT Thanjavur, there is a less chance of eligibility of merit seat in IIFPT Thanjavur.

Hello,

Eligibility criteria for IIFPT:-

1. Candidate must have qualified JEE mains
2. Candidate must have secured 55% in 12th for general category, 50% for OBC and pass percentage for SC/ST/PwD.

so as you mentioned your Board exam score, you have passed 12th which indicated you are eligible for the institute. Now

Hi

According to the question you have asked firstly we will provide you with the table of cutoff for iift

tanjavur

JEE MAIN stop 2016

COURSE CATEGORY ALL INDIA QUOTA

Closing Rank

Bachelor of Technology [B.Tech.] (Food Process Engineering) General 44531

Bachelor of Technology [B.Tech.] (Food Process Engineering) Schedule Caste

Hi,

Percentiles are very misleading if not analysed properly. 80 percentiles converts to a rank of about 1.72 lakh. Your actual marks might probably be around 70– 80 . At such marks and ranks, you won't get any NITs .

With such score you have some chances to get seat

Hello aspirant,

To get admission in IIFPT, the candidates should score a percentile more than 96 in JEE MAINS 2020 to get admission with the choice of your branch.

Hope this helped.

Thank you.

Greetings, aspirant!

Most of the Medical colleges in India that are private demand very high fees. The Government managed colleges are low of fees; however, the competition to get into one of these colleges is very, VERY high. The ratio of available seats to the number of applicants is almost