IIT
Hello Aryan!
I hope you are having a nice day!
I would like to inform you that the concerned authorities will release the cutoff of JEE Advanced 2020 for IIT Hyderabad in online mode. The minimum ranks required by the candidates to get admission at the institute will form the
Following are opening and closing ranks for different categories for CSE in IIT Kharagpur:
Category Opening Rank Closing Rank
Open 204 283
Open (PwD) 6 6
OBC-NCL 81 119
OBC-NCL (PwD) 8 8
SC 17 72
ST 17 39
for more information regarding opening and closing ranks, kindly visit the
Dear Aspirant,
IIT kanpur kanpur
Closing rank-919
IIT roorke
Closing ranks-416
IIT bhu
Closing ranks-2493
If you want to know about cutoff for top IITs then you can visit the link mentioned below
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-advanced-cutoff-for-iits
Thanks
All the very best
Any query related to upsee
Contact to Deepanshu sir-8787241374
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