Hey!

Cut off of Indian Institute of Technology  Delhi (IIT) changes every year. But according to previous years records:

• Closing rank to get admission in IIT DELHI through jee advanced is around 9,000 at which you will most probably get textile engineering.
• Then at ranks nearby 5,000 you will get biochemical engineering and biotechnology.
• Around 3,000 you will get chemical engineering.
• And if you  get rank below 500 you will get computer science.

For more information about the closing ranks, visit the link given below

https://www.careers360.com/university/indian-institute-of-technology-delhi/cut-off?college_id=2&exam_sub_exam_id=36&gender_id=2&counselling_id=548&caste_id=2

Thank you.

Hello,

In 2019 the cut off were as follows for SC and ST category respectively for each branch

• Biotechnology: 1720, 741
• Chemical: 753, 333
• Civil: 681, 74
• CSE: 39, 19
• EE: 152, 54
• Mech: 310, 1008
• P&I: 1372, 660
• Textile Technology: 2162, 1020

However, cut off is subjected to change it may increase or decrease slightly.

You can predict the college by using our JEE main college predictor

https://engineering.careers360.com/jee-main-college-predictor

Hello,

Even with your roll number your details can be traced out linked with your roll number in your college.So you may not face problem if you have given your roll number in place of your registration number.As long as the details which yiu have filled in the online application are true you will not face any problem.

• IIT Delhi-Energy Science,Energy Studies,Engineering Analysis and Design
• IIT Gandhinagar-Electrical Engineering

Hello

There are two types of tuition one is sponsored and one is non sponsored. In non sponsored tuition the admission is done solely on the basics of the merit i.e the admission is done on the basics of the qualifying rank got in the entrance exam.

Sponsored means the student didnt have enough merit but has done something exceptional.

Hope this helps.

hi vidushi,

Its not possible if you are general/obc candidate for whom rock engg cutoff for  2017-18 is as follows:

general (civil engieering): 712

general (civil engieering): 665

obc (mechanical engieering): 820

obc (mechanical engieering): 800

But if you have sc/st quota then you can have this course.

sc (civil engieering): 393

st (civil engieering): 393

sc (mechanical engieering): 299

st (mechanical engieering): 250

I hope this will help!!

all the best for the future!!

Hello Aspirant,

Due to this epidemic there has been a lot of changes made in the education system.

All of the exam dates and various procedures for admissions are postponed.

It may be possible that last date of filling up the form can extend due to lockdown.

So for this you need to keep a regular check on the website for the latest updates about it.

Hope it helps.

Good Luck!

Dear Shalu,

Your rank is good. IIT Kanpur has released the cutoff for IIT Jam. You can check it in their official site. cutoff marks for this year is 33.65 for general category. cutoff for EWS category is not given.  Score card will release in the end of this month so check it.

to know complete details, please check the link below:- https://university.careers360.com/articles/jam-cutoff

Thanks

Hello Ram

It depends upon your Stream. If you are from Physics or Chemistry Department then your course is bit more research-oriented and hence you can prefer going for a Ph.D. in some foreign university.

You can also opt for Mtech or MBA after your Msc.

Fees is around 56k(including Hostels).