Indian Institute of Technology
Hey,
This is something you need to work on yourself. Once in your life just forget about your reservation and try to think yourself as an unreserved category student.
If you do that and make yourself believe that you will see that you will be inspired to work on your
Hi,
Basically, aim for a two-digit rank. After that, select the relevant branch.
Ranks Range (General Category):-
2-100 for Computer Science
100-500 for Electrical Engineering/mathematics and computing
500-800 for Electrical Engineering (Power and Automation)
500-1200 for Mechanical
2000-3200 for Chemical
1100-3400 for Civil
3900-6500 fo textile
If you are from
Hello Aspirant,
According to the percentile you have mentioned your CRL rank is expected to be in the range of 153450 - 172500 , you can check out marks Vs CRL ranks Vs Percentile from the link given below :-
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
Or
You can also use JEE-Main Rank Predictor to
Hi Praveen,
The answer to your question could have been more specific had you given options of other universities to compare with. Nevertheless, speaking generally, the online data science course created by IIT Madras has a fantastic curriculum, but at the same time a big problem lies in the fact
Hello,
Yes, a candidate who has graduated from IIT. The eligibility criteria to appear for UPSC Civil Services Entrance Examination is that a candidate must have passed Bachelor's Degree in any discipline from a recognized board. The minimum age as of August 1 in the year of appearance in the
Hello student,
Hope you are in best of your health. So , I would suggest that always listen to your heart and take decision , age is just a number , if you want to crack iit and you think you just need a little hardwork with smartwork and you
For Jee Advanced 2020 the Minimum Percentage of Marks in Each Subject for SC Category was 2.50% and Minimum Percentage Aggregate Marks was 8.75%.For knowing the detailed cutoffs and cutoff trends you can visit this link- https://engineering.careers360.com/articles/jee-advanced-cutoff
Also the cutoff changes every year as it is based on several factors
As we go through the latest cut-offs of 6th round of JOSAA counselling 2020 then it shows that the closing rank for Open/General category was 8247 for Agricultural and Food Engineering branch in IIT Bombay.
As you are asking for marks to be secured in JEE-Advance for IIT
Your overall expected rank is expected to be in between 470580 - 529000. You can check the expected rank using our JEE Main rank predictor tool
https://engineering.careers360.com/jee-main-rank-predictor/
Last year the qualifying cut off for JEE Main for SC category was 50.1760245 percentile. This year it is expected to be
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