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Indian Institute of Technology Madras

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check my eligibility in IIT Madras

Tanya Gupta 29th Feb, 2024

Hello,

The eligibility criteria for admission to IIT Madras typically include a minimum of 75% marks in Class 12th (or equivalent) exams and a valid score in JEE Advanced. This is a basic idea of eligibility for IIT Madras. Please mention any specific course that you want to know eligibility.

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Question : Select the correct statement about the achievements of Sruti Bandyopadhyay, an eminent Manipuri dancer.

Option 1: She received Padma Shri for the year 2020

Option 2: She received the Sangeet Natak Akademi Award for the year 2020

Option 3: She received Kalidas Samman for the year 2020

Option 4: She received Padma Vibhushan for the year 2020

Team Careers360 25th Jan, 2024

Correct Answer: She received the Sangeet Natak Akademi Award for the year 2020


Solution : The correct option is she received the Sangeet Natak Akademi Award for the year 2020.

Sruti Bandyopadhyay was born on October 8th, 1962. Since 1998, she has held the prestigious title of a 'Top' Grade

30 Views

Question : Select the most appropriate option to fill in the blank.
Shakuntala Devi was born on 4th November 1929. In her childhood she________ to school.

Option 1: never gone

Option 2: went never

Option 3: had never been

Option 4: ever been

Team Careers360 25th Jan, 2024

Correct Answer: had never been


Solution : The right choice is the third option.

Explanation: "Had never been" is the correct choice because it indicates that during her childhood, she never attended school. This construction uses the past perfect tense to convey that the event or action never happened

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Question : The sides of similar triangle $\triangle ABC$ and $\triangle DEF$ are in the ratio of $\frac{\sqrt{3}}{\sqrt{5}}$. If the area of $\triangle ABC$ is $90 \text{ cm}^2$, then the area of $\triangle DFF\left(\right.$ in $\left.\text{cm}^2\right)$ is:

Option 1: 150

Option 2: 152

Option 3: 154

Option 4: 156

Team Careers360 24th Jan, 2024

Correct Answer: 150


Solution : Ratio of their sides = $\frac{\sqrt3}{\sqrt5}$
$\therefore$ Ratio of their areas = $(\frac{\sqrt3}{\sqrt5})^2 = \frac{3}{5}$
Given the area of $\triangle ABC$ = $90\text{ cm}^2$
$\therefore$ Area of $\triangle DEF=90\times \frac{5}{3} = 150\text{ cm}^2$
Hence, the correct answer is 150.

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