Hello Aspirant,

It's difficult to tell you the exact about the admission possibilities. But as per the previous year cutoff the chances are less to get a seat in IIIT Bhubneshwar or any other IIITs, NITs as General category for B.tech programme.

How ever you can go for the state

Hello,

Your rank can be calculated by this formula: 100 - your total percentile)*869010/100. Your estimated rank would be  44,144.

If number of students for April Exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 1200000/100.

According to 2019 cut-offs for OBC at

Hello Ashwin

Here is your list:

IIIT Hyderabad

IIIT Allahabad

IIIT Bangalore ~ International Institute of Information Technology

IIITM Gwalior ~ IIITDM Jabalpur

NIT TRICHY

NIT ROURKELA

NIT SURATKAL

NIT WARANGAL

NIT KURUKSHETRA

NIT DURGAPUR

MNNIT ALLAHABAD

NIT CALICUT

MNIT JAIPUR

MANIT BHOPAL

Hii

For your percentile,  your possible rank according to this formula will be-

(100- your percentile)* number of students appeared/100

106000 to 146000 in general category.  Your OBC rank will be more or less one third of general rank.  Generally an OBC candidates can get NITs and IIITs till 14000

Hi tgere,

You can calculate the Jee rank using this formula 100 - your total NTA score × 869010/100. If the number of candidates are increasing in April session then your rank will be 100 - your total NTA score × 1200000/100

With this formula your Jee rank will be

Hi Virabhadraiah.

With 95.9031489 percentile in this year's January JEE Mains, you can expect an estimated All India Rank of around 35,000. This rank was calculated using the formula (100-95.9031489)*869010/100. You AIR will increase if the number of candidates appearing for JEE Mains in April increase.

Now, with this All

Hello,

Daiict is a better choice then iiit at the moment, mostly because daiict is more established then iiit Vadodara at the moment as it is a fairly new institute. It has good campus facilities, faculties and handsome placements,however the brandname of iiit is much known

hope it helps

Hi Sanket!

Competitors who have finished 10+2 or equal level test with science stream in 2019 or 2020 are qualified to apply for admission. Applicants will be admitted to IISER just through after three channels.

1. Kishore Vaigyanik Protsahan Yojana ( KVPY ) channel
2. Joint Entrance Examination ( JEE-Advanced ) of

HELLO JAIGANESH
Congratulation for your result and You have a very decent chance of qualifying JEE mains. It is very difficult to predict the actual rank since it depends on various factors.N Now the expected rank for you present percentile for January session comes out to be 54313 general category.

Hii

Congratulations, your score is really very high.  For this score your rank will lie in range 4300-5900. For this rank you can get admission in many of NITs and IIITs

Some of IIITs predicted are- allahabad, Delhi, and them all newly setup one, gwaliour and jabalpur.  For predicting college