Vaishali, NTA has recommended the following instructions for uploading of images:

Uploading of Photograph: Instructions

Must be latest passport picture in a white background with the Name of the candidate and date written on the photograph. The Size must be 50 Kb to 300 Kb and format should be JPG.

Hi dear,

Your son scored 612 marks and rank is 22767. With this rank it is quite difficult to get MS surgery in all india quota. His rank must be under 9k. You can check details here

https://www.google.co.in/url?q=https://medicine.careers360.com/articles/neet-pg-cut-off&sa=U&ved=2ahUKEwiT3JeQ-a3nAhWM7XMBHZ72AUoQFjANegQIBhAB&usg=AOvVaw38lcM4UetgpkJOvPVFWPJE

Hope it helps.

Hello,

Allen institute is one of the best coaching institutes in Kota which assists the students to get ready for various competitive examinations. Doing coaching from class XI sets an ample time for the student to get ready for their board examinations and competition in parallel. More and more practice

NBE did open the correction window from December 19th to December 21st. If you missed the opportunity to correct thr originally uploaded image, we are afraid you might have missed the opportunity to appear for NEET PG this year. Any request or mail for changes in information after the closure

• Divide your subjects into 3 categories: the subjects that are difficult but you like it, the subjects that are difficult and you don't like it, the subjects that are easy.
• Now, start with the difficult subject that you

Hello student correction in neet 2020 application form begins on January 15 2020.last date to edit the details 31st January 2020. Those who upload wrong photo signature get notified by NTA. Candidates who will receive the SMS and email from NTA regarding application form correction should re-upload the scanned documents

Once you have entered any information, the correction window is the last chance to make any corrections. Post that NBE will neither entertain any requests for corrections or make the changes on its own. So what you enter there in the application form stays final once the correction window is

Hey,

We know that Cp-Cv= r

But we also know that, Cp-Cv= R/M (M is the molecular weight)

Therefore, r=R/M.

Now, for hydrogen, Cp-Cv=a

So, a=R/2 ( 2 is molecular weight of hydrogen)

For nitrogen,

b = R/28

So, ratio a/b =( R/2)/ (R/28)

a=14b

Hope this helps!