JEE Main Paper 1
Hello!
First of All you should check that you fulfill the eligibility for admission in IIIT .
The Eligibility are :
Candidates can get admission at IIIT on the basis of total marks obtained in Paper 1 of JEE Main and aggregate in Class 12th or any other equivalent exam.
Hello Aspirant, The calculation of the marks & rank would be difficult based on your percentile. You may calculate your expected rank by this formula 100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So
hello aspirant..
The difference between the jee paper 1 and 2 is that paper 1 is for the btech engineering courses and the paper 2 is for the barch architecture course. If you qualify these exams you will be eligible for the admission in nits as well other colleges accepting
Admission to the Bachelor of Science (Research) Programme - 2020 in Indian Institute of Science (IISc) will be based on the merit list of JEE Main - 2020 or JEE Advanced - 2020 . Minimum percentage required in these examinations are 60% for General, 54% for EWS, 54% OBC-NCL and
Almost 20-25 correct answers with no negative marking.....very rough estimation though
Chaithanya, while it is difficult to estimate your category rank, you can calculate your approximate rank in the Common Rank List for JEE Mains using your percentile through the following formula:
(100-your total percentile) x 869010/100
So with 94.1463772 percentile, your rank would be around 50868.
Also, if the number
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