JEE Main Paper 2
Hi Aysha,
You got 98.4 percentile in JEE main exam, your rank would be approximately in between 1500 to 2000. Also, you can check your expected rank using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112680,
Hello!
As per official notification, class 12th result 2020 CBSE will be declared by June 15, 2020. Pending exams of class 12 have been cancelled.
Students can check their result on cbseresults.nic.in
For more updated details kindly check on CBSE official websites.
Thankyou!
Hope it helps!
Hello,
Your expected overall rank will be around 3346. You can calculate it by the formula (100-your total percentile)*112679/100
112679 is the total number of candidates appeared in JEE Main Paper 2 in January session. Considering 2019 cut you may get seat in
However,
Hello aspirant
With 95 percentile your expected all India rank will be around 430,450.5 which is calculated by the formula
( 100- your percentile) × 869010 ÷100
Where 869010 is number of candidates appeared in January Jee mains 2020
95 percentile is quite good score but it's difficult to say
Hello!!
Hope you are doing great!!
JEE Mains is a national level entrance examination which is conducted for 300 marks.
Considering your percentile mentioned:
Your All India rank would be approximately around 85322,calculated by using the formula 100-90.18161*869010/100 where 90.18161 is your JEE Mains percentile and 869010 is the number
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