You got 95.8 percentile in JEE main exam, your rank would be approximately in between 4000 to 5000. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680, your rank

Hi there,

In jee mains 2 the paper will be of 100 marks, hence in order to score a decent percentile of more than 97 you need to score more than 60-70 marks in the maths paper.

And also it depends on the set if the set will be easy

No, BTech planning and Bachelor of planning are the same. The admission process for Bachelor in planning is done considering your JEE main paper 2 score , whereas the admission criteria for B.Tech planning in JNU, is done on the basis of your EAMCET score. You need to qualify and

• Know your JEE Main 2020 syllabus
• Understand the exam pattern of JEE Main
• Make the JEE Main 2020 preparation plan
• Books to refer
• Practice till you are perfect using mock tests and previous year papers
• JEE Main Exam Day Strategy

In 2019, an All India Rank of 1189 was the Opening Rank for NIT Trichy under B.Arch programme and 2468 was the Closing rank. Now this is 2019 data and cut offs change every year depending on various factors no.of Candidates appearing for the exam, no.of seats available, Difficulty of

Yash, you haven't mentioned the exam yo are enquiring about. Neverthless, once you fill in an application form and its correction period is over, you cannot make any changes to it. You also cannot claim benefits to the options you haven't chosen. So if you have selected NO for NCL

Hello aspirant,

For score or marks between 201 to 250 the estimated rank is between 1493 – 5752 for paper 2.

Thank you

Hello,

To write the mock test follow the following steps

• Go to the official website of NTA ( nta.ac.in (https://nta.ac.in/) )

• Open the JEE Main Mock Test 2020

• The candidates will have to choose their choice of exam and respective paper.

• Click on the "Start Mock Test" button on the