JEE Main Paper 2
Hello,
We can calculate your rank using the below formula
100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.
So rank formula is (100 - your total score) X 112679 /100.
So your rank will
The university has not given the cutoff list so it is impossible to say you the cutoff for NATA or JEE main.Try to score 80% of the total marks to be eligible for the university and other top colleges too.
Barch at Manipal University is a 5 year duration
Hi dear,
You have scored 84 percentile in JEE main paper 2 that means your rank should be around 18k. You can also calculate your rank as
Rank=(100-your percentile)×112679÷100
Last year cutoff of SC category was 525 for female. You can also check here
https://www.google.co.in/url?q=https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-trichy&sa=U&ved=2ahUKEwi7pMmknKnnAhUp4zgGHWSyBWQQFjAQegQIBBAB&usg=AOvVaw2JX_eYpbFfZHVUiQCNheBj
You have a chance to
Hi Suraj.
Well, SRM does not take admission based on JEE mains marks/rank. It is a private college and has its own exam called the SRMJEE. It is conducted every year like JEE Mains and the ones who clear the cutoff get into their respective branches. You can check out
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
