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Joint Entrance Exam Advanced

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219 Views

Am I qualified for JEE advanced with NTA score or percentile of 70 ?I have OBC -ncl quota as well

Deepak Kumar 20th Jan, 2019

Hello, dear

 Wellz use the below formula to find your normalisation rank , 

Rank= (100- your total score )×1400000/100

Considering 14lakh total number of student appear in exam.

And put your percentile in place of total score .

If you are getting rank around ,2 lakh AUR below 2 lakh

246 Views

I got 91.68 percentile will this be enough to give jee advance

Vikas gehlot 20th Jan, 2019

Hello

Greetings

Your percentile is 91.68 It means 91.68% student of the Total student appeared for the Exam are Behind You Therefore 8.32% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 72755.8

Your Rank would change Either Your Percentile Score

56 Views

i got 51% will i qualify for jee advanced my catageory is bc

Deepak Kumar 20th Jan, 2019
Hello, dear

Well, use the below formula to find your normalisation rank 

Rank = (100-your total score)×1400000/100

Considering total number of students appear in exam equal to 14lakh .

An put your percentile in place in total score ,

You will get your rank , so if your rank is
144 Views

I got 82percentile will i be eligible for jee advanced exam?

Vikas gehlot 20th Jan, 2019

Hello

Greetings

Your percentile is 82 It means 82% student of the Total student appeared for the Exam are Behind You Therefore 18% students of the Total students appeared for the exam are Ahead of You, Therefore Your calculated rank is 157404

Your Rank would change Either Your Percentile Score

142 Views

Is 85.4 percentile enough to apply for JEE ADVANCE exam??

dhameerbhatia31_7970609 Student Expert 20th Jan, 2019

Hello Raj Barman,

The cut-off will be announced in April for jee advance, so you have to wait till april to know the cutoff for JEE Advance because it will depend upon the number of students appearing in April too.


You can use the formulae given below to claculate your

127 Views

Hi sir good evening. I am Sai. I am doing my college 1st year this time I got 51 percenin jee main 2019.Am I eligible to write jee advanced?

Maligaveli sai pavan 20th Jan, 2019
Hello Aspirant

It is difficult to predict the cutoff because this year the jEE mains exam held twice so the results are based on two exams best score is considered.

So you have to wait until the official cutoff and qualifying marks are released.on the Month of April the official
402 Views

my percentile score is 79. am i eligible for advanced?

dhameerbhatia31_7970609 Student Expert 20th Jan, 2019

Hello Ipsita Rath,

The cut-off will be announced in April for jee advance, so you have to wait till april to know the cutoff for JEE Advance because it will depend upon the number of students appearing in April too.

You can use the formulae given below to claculate your

133 Views

I am open category student.i have scored 87.056 percentile am I eligible for jee advanced?

Arunima Singh 20th Jan, 2019

Hi Vaishnavi,

Since the next round of JEE Main Exam is going to be held in April, only after which the final results including the cutoffs, percentiles and ranks, for all categories, will be announced; I advice and also request you to kindly wait till April 30th. 

Predicting whether you

265 Views

My nta score is 80% am i qualified for jee advanced

Arunima Singh 20th Jan, 2019

Hi Reeja,

Since the next round of JEE Main Exam is going to be held in April, only after which the final results including the cutoffs, percentiles and ranks, for all categories, will be announced; I advice and also request you to kindly wait till April 30th. 

Predicting whether you

68 Views

I have 18.98 persontail in jee mains in obc which course I am eligible

Aditya Singh 25th Jan, 2019

Hello Aspirant,

Based on your percentile and category you are not qualified in jee main.Your percentile is very less to get you any course in jee mains.

You should start your preparation for jee main april attempt and try to score a good rank in it.

Hope your question is

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