Hello there,

With an OBC-NCL rank of 7,500 in MHT CET, you have a good chance of securing a seat in some of the top engineering colleges in Maharashtra under the state quota. Here are some colleges where you might expect to get a seat:

1. Government College of Engineering, Pune

Hello aspirant

for 7500 NCL OBC rank here are some colleges which u can consider

iit kharagpur = b arch.

iisc banglore =b.sc physics/biology/mathematics/chemistry/materials

iit bhu = b arch.

HEY ASPIRANT

From jee mains basis you can consider nit kuk cse ,iiest shibpur,nit surathkal,dtu, nsut,nit calicut,vnit nagpur,mnnit allahabad,mnit jaipur and many more nit

FROM jee adv basis you can consider

HELLO

With air 5552 general male u can get

FOR CSE ( or related branch )

iit palakkad,iit jammu,iit goa, iit dharwad,iit bhilai .

FOR ELECTRICAL

iit ism dhanbad,iit bhubaneshwar,iit mandi iit patna,iit ropar ,iit jodhpur ,iit tirupati,

FOR MECHENICAL

iit bhu,iit indore,iit dhanbad,iit mandi ,iit patna ,iit ganghinagar and

Yes

To secure admission to newer IITs, candidates typically need to attain a rank higher than 4500 in JEE Advanced. Generally, candidates aiming for IITs must achieve a minimum score of 250 or higher, falling within the 85-95 percentile range in JEE Main

Hi there,

Hope you are doing fine.

All of the colleges mentioned above are good colleges to pursue your studies. But choosing one from the above depend on a lot of factors like the academic curriculum, your area of interest and choice, the fees structure of the each college, the

HELLO

Here is the cutoff of previous year of greneral category

jee adv 2023 - 86

jee adv 2024 - 109

here is the cutoff of 2023 and 2024

2024 cutoff was highest from last many years

Hello reader,

kindly operate on the JOSAA portal, where you can open and register your account if you have a valid jee advanced or jee mains score. After uploading your scorecard, you can wait and keep checking the JOSAA website. If the cap list consist of your name in an

How do I know if I am qualified for appearing in JEE Advanced exam? A: Candidates need to check the JEE Main cutoff mentioned on their JEE Main result/scorecard anci see whether they have obtained aggregate percentile score equal to or above the cutoff. JEE Main cutoff is different for

Hello,

The weight of CO2 obtained by the complete combustion of 480g carbon is calculated as follows:

1. Atomic weight of carbon (C) = 12 g/mol

2. Moles of carbon = 480 g / 12 g/mol = 40 moles

3. Molecular weight of CO2= 44 g/mol

4. Weight of CO2=