Hello Aspirant,

Study material will help you to cover the syllabus but You should practice the Online Mock test online as JEE Main exam is Online.

You can also go for Careers360 JEE Main Knock out 2020 Preparation package.

JEE Main Knock out is completely online package based on Artificial

Hii

For your percentile your general rank can be calculated using this formula-

(100- percentile)*number of students appeared/100

That is in range 238000-326000

Last year the cutoff percentile for jee advanced was- 54

So you have high chances for qualifying jee advanced.  You can sit sit  counselling and may get

Hello student. All the students who give jee main donot have a motto of joining in iits. Because they wouldn't have preffered to join in iits from the beginning. They would have prepared for nits and given their best to get in top nits.

So this is the major reason

Hello Rajesh,

According to the given percentile your rank will be around 4,34,505. This rank is calculated using given formula :

(100 - your percentile)*869010/100

On the basis of this rank, a candidate cannot get any NIT but as you belongs to reservation category you can try for a chance

Hello,

To be eligible to get admission in IITs/NITs/IIITs a candidate must have passed 10+2 or its equivalent with atleast 75% aggregate for general category candidates, for SC/ST it is 45% from a recognised board or university.

So, it includes overall percentage which means including practicals and theory you must

Hello Sir.

There are several courses and numerous colleges that have a great scope in the future.

1. If not in IIT, then he can give other engineering examinations such as UPTU examination, BITSAT, VITEEE and many other examination.

2. He can puruse Bsc courses from some esteemed universities such