Hi sir,

At first heartly congratulations on success of your ward in AEEE 2021. See I don't think that he will be able to get either of the mentioned courses through JEE main scores as only 30 percent of the seats are filled by this mode and very high percentile

Dear sir,

If your son wants the Amrita main campus then for the ECE branch then it will be going to very tough if your son is not belong to home state category because their major preference is their home state students. You may get end up with not getting

Hello Aspirant,

As we go through the latest cut-offs of JEE-Main 2020 of JOSAA 6th round then it shows that :-

Closing SC rank for NIT Delhi was :-

• Electrical and Electronics Engineering branch - 3371 (Other state quota)
• Electrical and Electronics Engineering branch - 7262 (Home state quota)

So

There is a lot of advantages of appearing for LPU- NEST, including attractive scholarship. I would advise you to apply for LPU NEST, it's much easier that way plus it has more scholarship chances but without it also you can take the admission. Admission procedure is very simple in college.

Hello,

The marks which you have scored in your AEEE exam is a decent one but as you know that Amrita University is one if the popular and highly demanded University in India which is the reason that a good number of students every year try their level best to

Hi

with 71.19 percentile

• your rank will be around 294726 - 331315   as per our rank predictor at https://engineering.careers360.com/jee-main-rank-predictor

Your sc rank will be around 18k - 20k

To help you further,

To give you an idea of qualifying cut off, JEE mains 2020  qualifying  CUT OFF percentile  is given

Hi

It's quite difficult to predict because cutoff keeps changing every year depending upon various factors like :-

******number of students that appeared in the  jee main exam,

****** number of available seats,

****** performance of different students in the examination,

****** the category you belong etc.

But yes,

When

Though there is no such formula that relates OBC rank and CRL rank as it depends on various factors like total number of total candidates, number of candidates from OBC category, difficulty level of question paper. But for a rough idea I would say:

If your category rank is 500,