Joint Entrance Examination (Main)
you scored 90 marks in JEE Mains, your percentile depends on the overall difficulty level of the exam and the number of candidates who appeared. However, based on previous years' trends:
For 90 marks, your estimated percentile could range between 80-85 percentile.
This is an approximation, as the actual percentile
With 96.1 percentile in JEE Mains and KCET rank under 5000 (OBC 2A), you have a good chance for CS at PES University Electronic City campus.
For PES Ring Road (main campus), CS cutoff is usually under 3000 rank, even for OBC 2A, so chances are lower but possible if
When it comes to admission to Computer Science Engineering (CSE) at PES University , the candidate's rank in KCET and JEE Mains , as well as their category, play significant roles in determining whether they can secure a seat.
Here’s an analysis of your situation:
KCET Rank: With a rank
Based on your JEE Main percentile and KCET rank, here's an analysis of your chances for Computer Science (CS) at PES University:
With a 96.1 percentile in JEE Mains, your all-India rank would likely be in the range of 39,000 to 45,000 (this is an estimate and can vary slightly).
With a 96.1 percentile in JEE Mains and a rank less than 5000 in KCET under the OBC 2A category, your chances of securing a Computer Science (CS) seat at PES University are quite strong, primarily through your KCET rank.
PES University admits students through both JEE Main and KCET.
With 157 marks in JEE Mains, your percentile will be around 96–97, and your rank around 35,000–40,000.
As an OBC-NCL female candidate, it’s very unlikely to get CSE at NIT Trichy, where CSE closes under 2,200 rank (OS quota).
However, you may get CSE in newer NITs like NIT Puducherry,
Hii gunjan
As according to this year cutoff and previous year analysis it is tough ti get admission in nits or government colleges. But you can try in lower cutoff colleges and private college in any branch.
https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=paid
Check this for more information
Thanks
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