Hello Aspirant,

Congratulations for your good rank.

With this rank there is less chances for iit with  you core branches but you can get some other colleges don't worry.

Use this link to predict college.

https://engineering.careers360.com/jee-advanced-college-predictor

Feel free to ask any questions.

All the best for your future.

Hello Aspirant,

If your rank is 1053 considering SC category student these are the IIT’s you’ll likely to get

Core branches like Mech, civil, Ece in the below listed iit’s

IIT KANPUR , IIT KHARAGPUR, IIT MADRAS, IIT GUWAHATI, IIT ROORKEE, IIT VARANASI

And CSE in new iit’s.

IIT DELHI

Hello Aspirant,

As your JEE score is 82. And your SC rank is 26302. So your Percentile based on category is: 97.56 - 97.76  . Your Overall Percentile is: 93.27 - 93.47 . Your Rank based on category is:1763 - 3413  . Your Predicted Rank is:  59997 - 72147.

So

Dear aspirant
At first lots of congratulations for your results .

I can guess your score is about 25-30 and rank is about  400000-550000 .According to trends of previous years and this year's JEE MAIN cut off I am afraid to inform you that your chances of getting admission into

Hi aspirant,

You have obtained 78.89 percentile in JEE Main and belong to EWS Category. NTA released the rank and you would have seen yours and hence I need not mention it here. With such rank or percentile it is quite difficult for you to get into NITs. Nevertheless,  Now

Dear aspirant
At first lots of congratulations for your results .

I can guess your score is about 40-45 and rank is about  250000-280000 .According to trends of previous years and this year's JEE MAIN cut off I am afraid to inform you that your chances of getting admission into

Hi aspirant,

JEE Advanced result have been announced and you have obtained 13,92 SC category rank. To predict your college and branch options based on this rank, you can use our JEE Advanced college predictor tool by clicking on the following link: https://engineering.careers360.com/jee-advanced-college-predictor?icn=QnA&ici=qna_answer

Hope it helps you.