hey,

kurukshetra university , kurukshetra do  not offer any honour course what they do offer is listed below

1. B.E/B.Tech

2. B.S.c

3. M.E/M.Tech

4. B.Com (//B.Com)

5. M.A.

6. B.A.

Hope this helps!

Hello!!!!

Hope you are doing great!!!!

Kartik,Your All India Rank would be 104281 approximately,calculated by using the formula 100-88*869010/100 where 88 is your percentile and 869010 is the number of candidates appeared for jee mains in january session.As per the previous year scenario,it would be difficult to get seat in

Hello,

Your rank will be around 2,60,703 and the formula is (100-your total percentile)*869010/100 where 869010 is the total number of candidates appeared in January session.And category rank will be in between 15000-20000.In 2019 the round 7 cut off for Home state SC candidate for Mechanical Engineering was 5517, for

Hello,

Cut off is given in terms of closing rank and opening rank for each category and branch.In 2019 the round 6 cut off was follows for SC home state category for various branches

• EE: 5209
• Civil: 5581
• Production: 7231
• IT: 2004
• Computer: 1521
• Mechanical: 5432
• ECE: 3894

It is

Dear Aspirant ,

First of all there was no percentile scheme in 2016 , this is introduced privious year . And privious year closing rank for your category in NIT Kurushetra CSE was 1521 ( SC categoryn rank) in 7th round and 51k (All India Rank) in spot round and

Hello,

You have not mentioned your percentile.In 2019 these were the cut off SC home state category branch wise in round 7 JoSAA counselling in NIT, Kurukshetra

• CSE: 1521
• Production and Industry Engineering: 7597
• IT: 2004
• Mechnaical : 5517
• ECE: 3894
• Civil: 6282
• EE: 5209

To get such rank you

Hello,

You can calculate your expected rank by the formula (100-your total percentile)*869010/100

where 869010 is the total number of candidates appeared in January session.So by the percentile given by you, your expected rank will be around 330223 and your category rank will be around 28000-30000.With such rank it is

Hey Kartik

To get admission into NIT Kurukshetra, considering your category, one needs to score following score:

• Last year, the cutoff rank for Electrical for Home state, SC candidate was AIR 5201
• Accordingly you need to score around 200-220 marks out of 360, and for the new pattern you score

Hello!!!!!

Hope you are doing great!!!!!

kartik,Your All India rank would be 2,17,252 approximately,by using the formula 100-75*869010/100 where 75 is your percentile and 869010 is the number of candidates appeared for the january session.As per the previous year scenario,With this rank you can not get seat in both the