Dear aspirant

It would be better if you make clear which ASAT you are talking about.

But if you are talking for Allen ASAT then it's not cleared about minimum marks .

So it is going depend only the total on level of question asked

If you Scored around 200

Hello,

With  this percentile your overall rank in JEE Main will be around 244882 - 275282

Based on past years marks vs percentile data, your total marks obtained will be around 42-48 marks. The original marks scored by you may slightly vary depending upon your exam date and exam session.

Hello Aspirant,

Since you have not mentioned your category so considering it as General or Open category.

As we go through the latest cut-offs of JEE-Main 2020 of JOSAA 6th round then it shows that the closing rank for NIT Warangal was 24034 for Metallurgical and Materials Engineering branch in

Hello Aspirant,

Since you have not mentioned your category so considering it as general.

See it is quite difficult to help you with exact cut-off marks because it keeps on varying depending upon various factors but as we go through previous year's (2019) cut-off then it shows that in 2019

Hello Aspirant,

Since you have not mentioned your category so considering it as general.

As we go through previous year's (2019) cut-off then it shows that in 2019 the lowest cut-off marks was 575 for Maulana Azad Institute of Dental Sciences, New Delhi under state quota for General category and

Hello,

It is difficult predict the exact score as the total marks for JEE Advanced changes every year. Analyzing the past year trends you need to score minimum 55-60% of total score if you belong to general category, if you belong to SC/ST category you need to score minimum 50%

Hello sunnysathvik

I hope you are doing good.

You query is missing relevant information required to answer the query. I suggest you to provide necessary details like specific entrance name,category(important for analysis),university name you want to know about,so that I can help you better in  a precise way.

you can

Hi

With 89.4 percentile

• Your rank will be around 108438 - 121900 as per our rank predictor at https://engineering.careers360.com/jee-main-rank-predictor

89.4 percentile on 18th March 1st shift is around 90 marks.

For example,

With 90 marks

18, Mar 2021- Shift 1 was Moderately Easy and Your Overall Percentile is 88.61 -

Hello aspirant,

As of now it's tough to say what could be the cutoff because every year the cutoff changes due to many factors like total students appearing for exam, difficulty level of paper etc factors.but based on previous year analysis and your rank, category we can help you with