Marks
Hello Aspirant,
The KCET rank will be calculated by taking 50% weightage of broad marks and 50% of KCET marks.
Don't be demotivated, you have secured a decent rank.
According to this score your rank will be around 40,000 to 50,000 . This is the expected rank.
You can go
Hello,
As per KCET 2022 Marks vs Rank trend your rank is expected to vary in between 5000-15000. It is a decent rank and you will have good chances of getting seat in a decent institute. Marks scored in the qualifying examination that is 10+2 and KCET will be combined
Your marks in chemistry and maths are excellent. In physics, if you do the following things then you can improve your score.
Hello aspirant,
Hope you are doing absolutely great.
So with regard to your query, generally the criteria to get free seat in KL University is as follows:
JEE Mains: 95 and above percentile
JEE Advanced: 1 to 7000 All India Rank
EAMCET exam: 1 to 500 rank
KLEEE: 1 to
With your mark, you can rank between 114400 - 116400.
The cut-off for OBC is 245 and your score is 231. The score for deemed institutes will remain above 245.
245 is the minimum score required for an OBC nominee to qualify for the NEET PG exam.
All
Hi,
Hope you are doing well.
There are no any fixed method to calculate percentile. It depends on various factors like
There only prediction or assumptions are done on the basis of previous years data and
Hi Megh,
Since the Marks v/s Percentile data has not been released, here is a prediction from the past years' data. According to that, your estimated percentile is between 84.56203931-91.59517945. I used this article to predict this: https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
You may or may not be eligible for JEE Advanced based on
It is quite difficult to predict the exact rank based on your given marks because the rank Vs marks keeps on changing depending upon various factors such as :
** Number of candidates appeared for examination.
** Top score for that particular year.
** Total number of seats
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