Hello Harsh,

4 dices are thrown

then the outcome of the sums can be:

4,5,6,………………14……………..,22,23,24

Mid-point is 14. The left side of the midpoint is a mirror image of the right part.

So let's say the number of ways of getting a 20 is the same as the number of

hello aspirant,

your rank is in average category. hoever you may not get top ranked iits, but you may secure a seat in new iits like iit roorkee, iit jodhpur, iit patna, iit bhubaneshar etc.

please go through the below mentioned link to know the cutoff for iits

https://university.careers360.com/articles/jam-cutoff

It depends on how you see your career. Civil Services is very unpredictable. Think this way - what will be your career options if you cannot crack the exams in maximum attempts available. This is not to demotivate you. Interest in mathematics might lead you to some new heights in

Hello aspirant.

To become eligible for NEET examination, need to pass in all the subjects with 50% aggregate for unreserved category and 40% for OBC/SC/ST category .

So you need to pass in all the subjects to become eligible.

For more information about eligibility refer 

https://www.google.com/amp/s/medicine.careers360.com/articles/neet-eligibility-criteria

All the best.

Hello aspirant,  

Yes ut us mandatory to have maths as one subject in 12th class. Delhi University offers and conducts Bachelor's of Management Studies (BMS), Bachelor's of Financial & Investment Analysis(BFIA) and Bachelor's of Business Economics(BBE) , through Joint Admission Test, that are similar to BBA and it is compulsory

Ayushi,

As it's said :"Sometimes there doesn’t exist a marked linear relationship between two random variables but a monotonic relation (if one increases, the other also increases or instead, decreases) is clearly noticed. A Pearson’s Correlation Coefficient evaluation, in this case, would give us the strength and direction of the

Hey Aaditya,

Here’s the solution to the asked problem:-

(X+Y)^2 = X^2 + Y^2 +2XY

(Y+X)^2 = Y^2 + Z^2 + 2YZ

(Z+X)^2 = Z^2 + X^2 +2ZX

(X+Y+Z)^2 = X^2 + Y^2 + Z^2 + 2(XY + YZ + ZX)

Use the above equations to calculate the value. 4th

hello vipul

32/3 should be divided by 8/15 in order to get 20.

let the required number be y.

as given,

32/3 X 1/y = 20.

upon transposing,

32/3 X 1/20 = y

reducing it to the least terms, 

y =8/15.

so, 32/3 should be divided by 8/15 in order