Hello Ajay

Please find the question papers of Telangana board for both class 10 and 12 below.

https://school.careers360.com/boards/bse-telangana/telangana-ssc-question-papers

https://school.careers360.com/boards/tsbie/ts-intermediate-question-papers

Hi Aseera,
The following articles will help you to access your desired 10th SSLC Previous Year Questions.

• https://school.careers360.com/boards/dge-tamil-nadu/tamil-nadu-sslc-question-paper
• https://school.careers360.com/boards/dge-tamil-nadu/tamil-nadu-sslc-last-5-years-question-papers-with-solution

Hi Sanjith,
Here is the answer to your question.
Given:
$\begin{array}{rl}& 2{\sin }^6\theta {\cos }^6\theta -3{\sin }^4\theta {\cos }^4\theta +1=0\\ & \text{Let}x={\sin }^2\theta {\cos }^2\theta \end{array}$
Then:
$2x^3-3x^2+1=0$

You can check the past 5 years' question papers for CBSE class 10th: https://school.careers360.com/boards/cbse/cbse-previous-year-question-papers-class-10

Hi Paavni,

You can change your course from Bachelor in Fashion Technology to Bachelor of Design in NIFT. Please remember that Physics and Mathematics are compulsory in Class 12 for BFTech. However, BDes programme is open to all streams. Click on the link below for details:

• NIFT application process 2026

Hi Kamlesh,
A rectangle is a quadrilateral.
The sum of all interior angles of any quadrilateral is $360^{\circ}$. Each angle of a rectangle is ${9 0}^{\circ}$.
Therefore, $90^{\circ}+90^{\circ}+90^{\circ}+90^{\circ}=360^{\circ}$.

Hello!
SNUCEE level generally VITEEE se milta-julta, JEE se thoda easy hota hai. Aptitude aur Maths ke liye NCERT, VITEEE sample papers aur mock tests practice karo. Time management pe focus karo.

for more information SNUCEE

for more information VITEEE

for more information JEE

Hi Monish,
SNUCEE mainly tests aptitude, logical reasoning, and basic Class 11–12 maths. Prepare using aptitude books (RS Aggarwal), NCERT Maths, and practice mock questions similar to the VITEEE level. The exam is easier than JEE Main, so VITEEE preparation is usually enough to crack it.
You can also check