Dear student,

JNTU Karimnagar is good college for pursuing B.Tech in Mechanical Engineering.

They have total 60 Seats.

The average salary package offered is 5-6lakh per annum.

You can read more about it by clicking the link below-

https://www.careers360.com/colleges/jntuh-college-of-engineering-karimnagar/btech-mechanical-engineering-course

Hope it helps!

hello aspirant,

the first thing that should be in your mind is about the interests, if you have interest in taking CSE, you should surely take it , but the placement factor is also important, so, it's always preferred to choose IIT over any other local private college because the

Hello Aspirant,

The quality of these three colleges is same, And according to good professor I'm suggesting you to take admission in SNIST. In SNIST Professors are highly educated. They are well experienced. They are friendly in nature. Professors helps student. And SNIST labs for mechanical engineering is better than

• Around 65-70% placement.
• No of companies visited - 246 in 2018
• Package varies from 7 LPA to 26 LPA.

• Around 72% placement.
• Average package is 10 LPA.
• Top recruiter are Bajaj,

hi,

basically gate exam is based on 10-12 subjects of your full 4 years engineering course. so you may understand that you dont need to study the full syllabus of engineering. you have to follow the strictly gate syllabus and study accordingly. now mathematics and aptitude is common to all.

I think unless genuinely interested in Mechanical Engineering, you should opt for Metallurgical or Chemical at NIT Rourkela. NIT Roukela is one of the Best NITs of India, and probably the Best when it comes to core branches. It has excellent faculty, infrastructure, facilities as well as a huge campus

Dear Student,

Both of the above colleges are National Institute Of Technology.
The better option for you completely depends upon your field of interest, your aspirations and the place you prefer to attend your college.
But, sometimes it's depend on us because we the students of NIT ca give the

Hello,

a)Distance from earth's centre = 6400 + 640=7.04 x 10^6m

Now,

mv^2/r= GMm/r^2

V =   √GM/r  = √56.8 x 10^6

= 7.56 x 10^3 ms ^-1

(B) Total energy after 1500 rounds = Initial energy - Energy loss

= - GMm/2r- 1.42 x 10^5x 1500

=(- 6253-0213) x 10^9