Hello Candidate,

Here are the general steps to convert any function into triplets- 1. Temporary Variables are not used, and references regarding the instructions are made.

Steps to convert a function into quadruples- op in the operator field, y in the arg1 field, x in the result field, arg2 field remains unused.

Hope that this information was helpful for you!!

Good good luck.

Hello aspirant,

Hope you are doing well,

The exact date of application for NATA 2021 haven't been released yet but they have given that they may be releasing online application in 4th week of January 2021.

NATA important dates for session 1

NATA important dates for session 2

Hope this information helps,

Best of luck

Dear aspirant

NATA application form may be release in 3rd week of January 2021. Application fees for different candidate are

• Irrespective of his/her gender, a candidate applying for NATA– 2021, either first test or second test, have to pay INR 1800/- (Rupees One thousand and eight hundred only) as application fee, through ONLINE mode. This is inclusive of service fee charged by the bank.
• In case the Candidate wishes to appear for both first and second test, he/she shall deposit Rs 3800/- (Rupees Three thousand and five hundred only) as application fees.
• Candidates belonging to SC/ST category need to deposit Rs 1700/- for either first or second test and Rs 3100/- for appearing in both the tests through online mode.
• Candidates opting to appear from test centres outside the territory of India have to deposit Rs.10000/- for either first or second test and Rs. 18,000/- for appearing in both the tests through online mode.

Hope this information helps you

all the best !!

Hello aspirant, as you mentioned that you secured 150.75 in NATA 2020.

NATA 2nd exam result 2020 has been announced on September 18. CoA conducted NATA 2020 second test on September 12. NATA first attempt exam was conducted on August 29 and the result has been announced on September 4.

Your admission through NATA is based on your merit system. Divide the NATA score by 4, and your CBSE result by 2, and add them to find your merit out of 100. Normally colleges accept a student who has 60+ merit overall, and sometimes colleges even go for lower merit.

For the cutoff of various colleges accepting nata marks visit NATA 2020

Hope this helps

Hello aspirant,

As you mentioned that you secured 65.23 percentage in boards and 140 in NATA. And you belong to general category.

NATA 2nd exam result 2020 has been announced on September 18. CoA conducted NATA 2020 second test on September 12. NATA first attempt exam was conducted on August 29 and the result has been announced on September 4.

Your admission through NATA is based on your merit system. Divide the NATA score by 4, and your CBSE result by 2, and add them to find your merit out of 100. Normally colleges accept a student who has 60+ merit overall, and sometimes colleges even go for lower merit.

For the cutoff of various colleges accepting NATA score please visit NATA 2020

You haven't mentioned your query clearly. Whatever with 93 percentile score you will have very good College opportunities. Even if you are from reserved category there would be opportunities of getting NIT or IIITs as well. And for Nata admission is based on your merit system. Divide the NATA score by 4, and your CBSE result by 2, and add them to find your merit out of 100. Normally colleges accept a student who has 60+ merit overall, and sometimes colleges even go for lower merit. So as you have above 70 score in NATA so hopefully you can get well established Institutes through it as well.

To predict College through JEE mains click on the link: https://engineering.careers360.com/jee-main-college-predictor

Hope it would be helpful.

You haven't mentioned your query clearly. Whatever with 93 percentile score there would be very good College opportunity. Even if you are from reserved category there would be opportunities of getting NIT or IIITs as well. And for Nata admission is based on your merit system. Divide the NATA score by 4, and your CBSE result by 2, and add them to find your merit out of 100. Normally colleges accept a student who has 60+ merit overall, and sometimes colleges even go for lower merit. So as you have above 70 score in NATA so hopefully you can get well established Institutes through it as well.

To predict College through JEE mains click on the link: https://engineering.careers360.com/jee-main-college-predictor Hope it would be helpful.

Hello Dear,

Sir JJ College of Architecture (SJJCA), established in 1913, is located at Mumbai, Maharashtra. The college is recognized by AICTE and is affiliated to University of Mumbai, Maharashtra

The college offers UG and PG courses in the Department of Architecture. At the UG level, Sir JJ College of Architecture offers B.Arch. and M.Arc. at the PG level.

Sir JJ College of Architecture offers B.Arch. at the UG level with a total intake of 67 seats. The basic eligibility criteria for B.Arch. is 50% marks in 10+2 with Physics, Chemistry, Mathematics, and English as main subjects of study from a recognized board.

Your NATA merit score is 150.75 marks there is a chance you can get Sir JJ college of architecture so its better to wait for the counselling and prepare for the next step.

Hope this helps.

Good Luck

MTech can be pursued only after MCA or BTech and therefore it is more time efficient for pursuing MSc in Computer Science.

M.Tech. in Robotics Engineering is a 2- year long course divided into 4 semesters, with each semester lasting a period of 6 months. The programme is designed for eligible candidates interested in designing, controlling and creating robotic systems.