National Institute of Technology Agartala
Dear Aspirant,
With 77 percentile in JEE Mains CRL Rank would be in the range : 235290 - 264500 (Approx.)
JEE Mains Rank/Percentile Predictor:
https://engineering.careers360.com/jee-main-rank-predictor
Now with this CRL Rank,
SC Rank might be around 15000(Approx.)
considering this rank range , SC Category Home State quota and previous year record of closing rank you might get ECE in NIT Agartala (As closing rank of NIT Agartala ECE for SC -Home State last year was 16242 )
**(This might change due to changing trends of JEE Mains every year)
You may check all previous year cutoff(closing ranks) of NITs, IIITs, GFTIs on official JOSAA website:
https://josaa.nic.in/Result/Result/currentorcr.aspx
Check -
JEE Mains College Predictor-
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hello,
You have done a really great job as you have scored a such a great marks and definitely you should try for top colleges as you also belong to OBC-NCL category which will be very helpful for you while securing admission and hence to know it completely get your rank first by the rank which is mentioned below:
After getting your rank you just have to compare it with all the colleges oc your list and than you will find which will be best college for approaching or else from the other link you can get to know in which colleges you have chance of getting admission on the basis of your rank:
Thank you..
Hello Aspirant,
As per the data you have mentioned in your question, the expected figure for you are :-
-->> CRL Rank - 286440 - 322000
-->> OBC Rank - 15000-16000
You can check out marks Vs CRL ranks Vs Percentile from the link given below :-
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
Or
You can also use JEE-Main Rank Predictor to predict your rank :-
On the basis of above figures you can go for the enlisted colleges only if you deserve Home state quota for them otherwise you should go with private colleges :-
And some more. You can check out previous year's cut-offs from the official website of JOSAA as given below :-
Note that the above list is merely a prediction which has been made on the basis of latest cut-offs available on official website of either JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.
So you can use JEE-Main College Predictor to predict your chances of admission in different engineering colleges of India on the basis of your JEE-Main 2021 result :-
You can also check out the expected JEE-Main 2021 cut-off and predict whether you have any chances to get qualified for JEE-Advance 2021 or not, so it is given below :-
** Common Rank List (CRL) - 90- 95 Percentile
** GEN-EWS - 70- 75 Percentile
** Other Backward Classes (OBC-NCL) - 70- 75 Percentile
** Scheduled Caste (SC) - 50- 55 Percentile
** Scheduled Tribe (ST) - 40- 45 Percentile
** PwD - 1-2 Percentile
Being a St candidate you have decent chances to get qualified for JEE-Advance 2021.
You can check out previous year's cut-off trends from the link given below :-
https://engineering.careers360.com/articles/jee-main-cutoff
I hope this information helps you.
Good Luck for your future!!
Yes sister of course you'll get CSE in NIT Agartala.
Hi
Since you have done class 12th and passed few years of graduation course, your code will be 05
Code for students who have passed first year of graduation course is 05
Code for students who have passed class 12th as highest qualification till registration is 02
Candidates who have passed any graduation course with physics, chemistry,biology/biotechnology- code is 06
Here are details about various qualifying codes to be followed in NEET -
https://medicine.careers360.com/articles/neet-qualification-codes
Dear student,
What is your category?
It depends on your category too but as you have not mentioned your category in the question paper then i will consider you as general.
Now if try to find your rank on 86 percentile then it will somewhere between 143220 - 161000.
Please note that this is expected rank range so you can expect some variation from the actual rank as it depends on various factors like number of students appearing in exams etc.
You can check your rank yourself by going through our rank predictor tool. I am pasting the link below.
Now the cutoff for NIT Agartala CSE last year(2020) was 18351 for a other state general student. And in previous it has been below 20000 rank for the seat of Computer Science and Engineering in NIT Agartala.
You can check the cutoff of NIT Agartala by going through the link below.
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-agartala
So analyzing all the these unfortunately you will not be getting CSE in NIT Agartala.
But you can check which colleges you can get on your rank range by going through our college predictor tool. Below I am attaching the link for it.
https://www.careers360.com/college-predictor
I hope this answer helps you.
All the very best!!
Dear Aspirant, with this percentile CRL rank would be around 3lac( 306900 - 345000 ). According to previous year cutoffs closing ranks there aren't much chances for NIT Agartala (BS MS Dual Degree in Maths) with this rank.
JOSAA official closing ranks(2020) - https://josaa.nic.in/Result/Result/currentorcr.aspx
You can check other options using these -
JEE Mains Rank Predictor- https://engineering.careers360.com/jee-main-rank-predictor
https://engineering.careers360.com/jee-main-college-predictor
Your profile suggests that your homestate is Bihar so you will be eligible for other state quota in NIT Agartala
With 70 percentile
your rank will be around 306900 - 345000 as per our rank predictor at https://engineering.careers360.com/jee-main-rank-predictor
Your obc rank will be around 1 lakh .
When comes to dual degree in mathematics then NIT Agartala offers Mathematics & Computing (5 Years, Bachelor of Science and Master of Science (Dual Degree))
I am extremely sorry to tell you but with above predicted rank you have a very low chance in NIT Agartala even in Mathematics & Computing (5 Years, Bachelor of Science and Master of Science (Dual Degree))
For example,
In 6th round of josaa counselling 2020, closing rank for gender-neutral for obc category was 12010 obc rank under other state in NIT Agartala for Mathematics & Computing (5 Years, Bachelor of Science and Master of Science (Dual Degree))
You can check the same at
Above prediction is on the basis of past year data but cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc so
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
To improve your score in remaining sessions of JEE main you should focus on your preparation go through previous year question papers ,mock test papers and to help you in your preparation we have jee main knockout out for you, for which is provided below
https://learn.careers360.com/knockout-jee-main
Thankyou
Since you have not mentioned your category so considering it as General.
If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2020 then according to the percentile mentioned by you in the question your CRL rank is expected to be in the range of 306900 - 345000 , you can check out marks Vs ranks Vs Percentile from the link given below :-
As we go through the latest cut-offs of JEE-Main 2020 of JOSAA 6th round then it shows that :-
Closing CRL rank for NIT Agartala was :-
So you have quite almost no chances to get NIT Agartala with Mathematics & Computing (5 Years, Bachelor of Science and Master of Science (Dual Degree)) even if you have Home state quota.
But yes if you improve your percentile in any further session of JEE-Main like around 80+ then you might have a shot at NIT Agartala with Mathematics & Computing (5 Years, Bachelor of Science and Master of Science (Dual Degree)) .
You can check out the latest cut-offs from the link given below :-
Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.
To have a list of all those colleges which you can get based upon your marks, category, and state you can use JEE-Main College Predictor:-
If you are preparing for JEE-Main 2021 or 2022 then I would recommend you to check the resources made by our experts to help aspirants like you in the best and smart preparation of JEE-Main 2021 or 2022 :-
https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA
You can also check out the JEE-Main 2021 qualifying cut-off (expected) for JEE-Advance 2021 from the link given below :-
Good Luck!!
I am extremely sorry to tell you but with above predicted rank you have a very low chance in NIT Agartala even in 5 Years, Bachelor of Science and Master of Science (Dual Degree)
In 6th round of josaa counselling 2020, closing rank for gender-neutral for obc category was 16589 obc rank under other state in NIT Agartala and it was for Chemistry (5 Years, Bachelor of Science and Master of Science (Dual Degree))
You need to get at least around 16000 obc rank to get a seat in NIT Agartala even for 5 Years, Bachelor of Science and Master of Science (Dual Degree) i. e at least around 94.5 percentile To improve your score in remaining sessions of JEE main you should focus on your preparation go through previous year question papers ,mock test papers and to help you in your preparation we have jee main knockout out for you, for which is provided below
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