National Institute of Technology Calicut
Hello aspirant
As you got 98 percentile in JEE Mains. Also, you have an obc quota so according to the previous cutoffs there are good chances for you to get CS branch in NIT Calicut. As, you have home state quota also, then you can get admission in 2th or
Hello Aspirant,
NIT Calicut ranks 23 by NIRF while NIT Surathkal has NIRF rank of 13 which makes it better than NIT Calicut and other NITs.
Talking about faculties, NIT Surathkal has more better faculty where most of them are from thermal backgrounds.
Placements are satisfactory in both the NITs
Hello,
You haven't mentioned whether you belong to OBC-NCL or OBC-CL, if you come under OBC-CL then you are considered as general category. Your overall category rank is expected to be around 6084 and you can calculate it by the formula (100-your total percentile)*112679/100 where 112679 is the total number
Hello student,
Actually you have not clear whether you get passed in 10 + 2 level or not. As you get failed in mathematics, it may be a problem for you in future in this engineering career.
But as per the official notice if you have passing certificate of 10
While it is a bit ambiguous with what you are comparing NIT Surathakal Nanotech. But talking in general, these two colleges are more or less in same level. If a company visits either of the two colleges, it generally visits the other too.
Speaking of general placements, past recruiters
Hi Aysha,
You got 98.4 percentile in JEE main exam, your rank would be approximately in between 1500 to 2000. Also, you can check your expected rank using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112680,
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