Hello,

MCA is masters of computer application. It is a three year long professional post-graduate programme for candidates wanting to delve deeper into the world of computer application development with the help of learning modern programming language. The programme is a blend of both theoretical and practical knowledge.

NIT Karnataka,

Dear aspirant,

As you are taking up MCA I would definitely recommend you NIT K because the college has really good placements. It has good research outlook. On the other hand Christ University is has a good infrastructure but it is not upto the mark as the nit K .

hi,

Its not clear in which domain you wants a transcript, generally after completing 12th course you would receive your marksheet of 12th result, pass certificate of 12th course, A transfer certificate or school leaving certificate from the respective institute. however for any other document you must consult with school

• Unreserved: 27128
• EWS: 4904

Hello Aspirant,

If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2020 then according to the percentile mentioned by you in the question your CRL rank is expected to be in the range of 64674 - 72703 , you can check out marks Vs ranks

Dear aspirant,

These things depends on many factors and it cannot be predicted accurately as the factors like toughness of the paper , the quality of students appearing in the exam , and the cut off decided by josaa change every year.

For prediction you can check out the link

Hello,

According to your percentile score your percentile would lie somewhere between 96.99-98.39,  considering your percentile 96.99, your rank would fall somewhere between 30792-34615.

To check your rank by yourself please go through this link

https://engineering.careers360.com/jee-main-rank-predictor

To check other eligible colleges according to your rank please visit this link

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hello,

CSE Branch cut off for general candidates in NIT Surathkal was:

• JEE 2020:   1324
• JEE 2019:   2156
• JEE 2018:   3928

and for NIT Trichy the cut off for CSE was:

• JEE2019:   1373
• JEE2018:   4048

So, you need to secure around 220 marks to secure your chance in these NITs

Hello Aspirant,

The package completely depends upon your caliber, knowledge and amount of hard work you put in. According to NIT Surathkal placement record, the average placement of signal processing and machine learning comes around 6 to 7LPA.

The package can go higher depending upon your previous experience and skills