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i have secured an NTA score of 45.1836004 in jee main 1st session, so what will be my expected rank

Shivanshu 21st Feb, 2024

Dear aspirant !!

Hope you are doing well !

You can go to our link given below ;-

Here you will find your rank by putting your percentile. This will give you the most accurate results than the other things roaming around the net .

Visit here ;-

https://www.google.com/url?sa=t&source=web&rct=j&opi=89978449&url=https://engineering.careers360.com/jee-main-rank-predictor&ved=2ahUKEwj-s8PdxrqEAxUvsFYBHaEbCIgQFnoECBUQAQ&usg=AOvVaw2QNQ0E4U1hgytKWWo9jfZm .

46 Views

I have entered wrong roll number of standard 11th standard in neet form of 2024 and I have not received any message from nta about wrong information or something like that. will my form get rejected or will I face any problem during counseling

satyamercedes0626 18th Feb, 2024

Hello aspirant,

Hope you are doing great.

As per your question, initially this might not create any problem, but during the counselling process, they may reject your application as you have provided wrong information. To avoid this, it is better to contact the authorities and explain your problem. They will

51 Views

I have mistakenly registered twice for JEE mains 2024 examination.For the april attempt i registered as a fresh candidate.Would i be banned for 3 years or my candidature would be cancelled or NTA will resolve my issue as i have mailed them already.

Satvik 15th Oct, 2024

Hi

hope you doing well

NTA strictly prohibits duplicate registrations. If they detect two registrations, they may cancel both applications.In some cases, candidates may face a ban for 1-3 years, but this is usually for intentional duplicate registrations or misconduct.

What you have to do now that:

  • Email Response: Since
6 Views

i have been appeared in 2nd shift on 27th feb and my jee mains score is 61.4 pls confirm my nta score

Satvik 12th Oct, 2024

Hi

hope you doing well

To calculate the expected NTA score for JEE Mains based on your percentile (61.4), we can use the following formula:

NTA Score=(Number of candidates scored equal to or below your score /Total number of candidates)/ 100.

Total Candidates: In JEE Mains, typically around 10-15 lakh

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