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Class x English exam Odisha Kalahandi

Shivanshu 21st Feb, 2024

Dear aspirant !

Hope you are doing well  !! The exam and questions paper of odisha board of each and every subject can be obtained from the link that is given below ;-

https://www.google.com/url?sa=t&source=web&rct=j&opi=89978449&url=https://school.careers360.com/exams/odisha-10th-board/amp&ved=2ahUKEwjs0tCtqryEAxWmnmMGHZinCbQQFnoECBUQAQ&usg=AOvVaw3km-77wy4qNYX0c4av519K .

Hope you will find it helpful !

Thanking you

16 Views

Pick the best college for Commerce in +2 in the city of Rourkela, Odisha.

Rishitha 15th Feb, 2024

Rourkela, located in the state of Odisha, has several Colleges known for their strong commerce education at higher secondary level.

Here are some of the best colleges for commerce for +2 education in Rourkela, Odisha:

  1. Rourkela government college
  2. Ispat Autonomous college
  3. St. Paul's School, Rourkela
  4. Guru Nanak Higher Secondary School
  5. Delhi Public School, Rourkela

These are some of the top colleges and schools in Rourkela, Odisha, known for their commerce education at the +2  level. You should research each institution's curriculum, faculty, infrastructure, and extracurricular activities to make an informed decision based on your preferences and academic goals.

21 Views

Im a female student of EWS category from state odisha. My NTA score is 80.82 . What does that mean and whats my percentile. can I get any NIT or IIIT?

Akansha Sharma 20th Dec, 2024

With an NTA score of 80.82, your percentile is approximately around 95-96, but the exact percentile can vary slightly depending on the exam's overall performance. Based on this score, getting into top NITs or IIITs may be challenging, especially for competitive branches like CSE or ECE. However, you may have a chance in other branches or in newer NITs/IIITs. It's advisable to check the previous year's cutoff trends for accurate predictions based on your specific score.

For more details you can visit the link given below

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

4 Views

Question : Directions: In the following question, find the odd letter cluster from the given alternatives.

Option 1: CBED

Option 2: JILK

Option 3: TSVU

Option 4: VZXY

Team Careers360 23rd Jan, 2024

Correct Answer: VZXY


Solution : Let's check the options –
First option: CBED; C – 1 = B; B + 3 = E; E – 1 = D
Second option: JILK; J – 1 = I; I + 3 = L; L – 1 = K
Third option: TSVU; T – 1 = S; S + 3 = V; V – 1 = U
Fourth option: VZXY; V + 4 = Z; Z – 2 = X; X + 1 = Y

So, the fourth option is different from the other three options because the difference in the position value of the letters is different. Hence, the fourth option is correct.

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