Dear Rakesh, that is an impeccable academic record that you have got. MIT Chennai conducts admissions to its B.Tech program through a single window counselling called TNEA conducted by Anna University. For being eligible, you should have scored a minimum aggregate of 50% in your 10+2. With your marks, irrespective

Hello Rakesh Kumar,

Firstly you have secured a great marks in the examination and to enter into the MIT college there is TNEA counswcouns procedure. And you have got very good marks so that you can have chances of getting mit for aeronautical engineering

All the best

Dear Rakesh, that is an impeccable academic record that you have got. MIT Chennai conducts admissions to its B.Tech program through a single window counselling called TNEA conducted by Anna University. For being eligible, you should have scored a minimum aggregate of 50% in your 10+2. With your marks, irrespective

Dear Rakesh, admission to MIT are based on TNEA Counselling. This is just a Counselling procedure and not an entrance examination. You haven't mentioned your Category.  But going by your marks, there should not be any doubt if you would be selected or not. We are sure you have decent

You may get in through the following entries-

Registration of Students with Scholastic Aptitude (ROSSA) entry if you have passed your post graduation in first division.

Orientation course for engineering graduates and science post graduates (OCES) at BARC Training School and its affiliates.

KS Krishnan Research AssociatesAssociates

Direct recruitment through

Hello Kirti ,

Colleges for MBA in LUXURY BRAND MANAGEMENT   in abroad are as follows:

• Curtin University Australia, World ranking 301.
• Coventry UNIVERSITY UK,World ranking 601.
• Birmingham City UNIVERSITY, World ranking 1001.
• UNIVERSITY of Dundee, World ranking 201.
• UNIVERSITY of Southampton, World ranking 118.
• UNIVERSITY of Lincoln,UK.
• Regent's UNIVERSITY London.

Hiii Kapil answer to your question is

Since the box is moved at a constant velocity,the applied force F just overcomes the frictional force f,i.e,

F=f=μmgF=f=μmg

∴∴ Work done W=FScosθ=μmgScos0W=FScosθ=μmgScos0

⇒0.25×20×9.8×2=98J

Hope you like the answer....keep asking we are always looking for you to help....may you have a very bright