Hello,

You may consider going through the official website of BHU for previous year paper provided below-

http://bhuonline.in/old-qus-paper-entr.html

Or, you can also consider going through the sample papers of BHU PET by Careers360 which will be extremely useful in your preparation-

https://university.careers360.com/articles/bhu-pet-sample-papers

Hii aspirant ,

Coming to your question I would like to tell you that can you please mention the name of the college in which you have taken the admission  for your MBA program .

HI!

This is the total syllabus and respective weightage for GATE.

1. General Aptitude - Average Weightage = 4

English Grammar, Sentence Completion, Verbal Analogies, Word Groups, Instructions, Critical reasoning and verbal deduction

Numerical Ability - Average Weightage = 11

Numerical computation, Numerical estimation, Numerical reasoning and data interpretation

2.

Hii Manab,

Yes you can appear for jee mains 2020,but if you qualify jee mains you are not eligible for giving jee advance.You can only choose colleges on the basis of your jee mains score.As for advance you need more than 75% in 12 from cbse board.

Thank you

Hi aspirant

For physics you should follow dc pandey for mechanics,resnic hardle,concepts of physics by hc verma etc are some best books for jee mains,other than this you should follow ncerts books,your coaching materials also.

hope this could help you,best of luck

Hii..

There are some eligibility criteria to get admission in DU for B.com and these are..

an aggregate of 60% and more are required in Hindi /English and combinations of three other subjects mathematics,accountancy , economic and business study/ commerce

inclusion of other subject than these three subject will lead

Hello

Divide your time subject wise so that you can devote time to each subject and can perform well in the exam. Speed and Accuracy both are the key factors to score good in the exams so you should work on enhancing your speed and accuracy and that will be

Hey Kanhaiya!

Displacement= a/2

Total energy=1/2 m* (omega)^2* (a)^2 ....(1)

KE when displacement= x is

1/2 m* (omega)^2* [(a)^2-(x)^2]

1/2 m* (omega)^2* [(a)^2-(a/2)^2]

3/4(1/2*m* (omega)^2* (a)^2) .....(2)

By dividing 2 by 1, we get: 3/4

Therefore total fraction is 3/4

Sorry to inform you but it's a career counseling website,