I would name the colleges in descending order of preference:

• Indian Association for the Cultivation of Science (they have started the integrated bachelors-masters program recently).
• St. Xavier's College
• Ramkrishna Mission Residential College, Narendrapur
• IISER, Kolkata
• Jadavpur University
• Presidency University

These are the best colleges to study Physics in Kolkata. If

Hello aspirant,

Well the syllabus is divided semester wise in PDF format,which is easily available on the website and ece basically deals with semiconductors,diodes, instrumentation, microprocessors,microcontrollers,signals and systems etc.

In terms of subject toughness, everything depends on interest and hard work.

Hope it helps.

Hello Dev!

Considering your rank in IPU CET 2019 for B. A (Hons)Economics, following provided is the list of colleges affilaited with GGSIP University for this respective undergraduate course where you can expect admissions:

• Vivekananda Institute of Professional Studies
  
• Maharaja Agrasen Institute of Management Studies
  
• Fairfield Institute of Management& Technology
  

Dear Aspirant 

Engineering is not going to be easy for you because you have to study math for two years out of your four years in engineering that means 4 semester. After that there are many subject like signal and control system, mechanics etc which require strong knowledge of math.

   Hi V k,

            Here is the solution for your query

x=(1+t^2)^1/2

Now we need to differentiate this twice, that is double differentiate it to find acceleration. 

x'=1/2(1/(1+t^2))^.5*2*t

=t/((1+t^2)^.5)

Differentiate using product rule:

x"= 1/((1+t^2)^3/2)

Hello sunil,

yes you can apply for the admission in seed technology in liberal college.The Liberal College, Luwangsangbam established in the year 1979, is the outcome of a long cherished Will and Desire of the people in the area.For more details about this college,you can go through the

Hi Karsang,

The transition from n=2 to n=1 will have the same wavelength. You can check it using the formula to calculate wavelength. 1/(wavelength) = R * Z^2((1/n1^2)-(1/n2^2)).

R is a constant. Z is 2 for He and 1 for H. put values of n1 and n2. and equate both