Hello Sir,

Here's your Request: (With Last dates)

JEE Main   Last week of September 2019

JEE Main Paper 2          Last week of Feb 2020

Advanced  2nd week of May 2020

BITSAT    2nd week of March 2020

KVPY      1st week of September 2020

KCET      4th Week of February 2020

MHTCET    4th

Hello Saurabh, 

Your question is not much clear but if you are pursuing B. Tech and you want to know about the different you tubers who reach B. Tech course then it would be best to find individual topic on you tube and then search for the top rated video

Hello Kavya, 

CUCET is a national level examination which is regulated by ten central universities jointly. It is a combined entrance test organized for providing admission into various UG, PG & other courses offered by the central universities across India. 

You can go through this link if you want to

hello there,

The number of merit lists published by the university depends on the vacancy of seats after the first round of admission/counselling. If there are any seats left, more lists will be published - which is not always very certain in a particular count/number. 

Here is a link where

If you belong to general category, then sorry to say you don't have any chance since the eligibility cutoff to apply in courses through NEET like for MBBS BDS BAMS BHMS or BPT courses you needed 134 marks and your total is 124 which is short of the eligibility criteria.

• They should have secured a minimum of 60% (50% for SC/ST/PWD) marks in aggregate in

Hello there,

The formula to calculate centripetal acceleration from radius of circle and speed of the particle is:

centripetal acceleration = [(speed) ^2]/radius

                                   = (15*15)/2

                                   =225/2

                                   =112.5  m/s²

Hope this helps.

Hello Padmakar!

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

        a = (50*50)/318.47

        a = 7.85m/s^2

Hope this