Physics - Class 11
Dear aspirant,
For finding the center of mass for two mass system we need to know the formulas which is( mass1*coordinate of x1) +(mass2*coordinate of X2)/ (mass1+mass2) and for y coordinate apply the same process which has been applied for finding x coordinate.
(B) Both A and R are true but R is not correct explanation of A
Acceleration decreases according to formula g′=g(1−R2h), where h is either height or depth and R is radius of earth. So, Acceleration due to gravity decreases as height or depth increases.
(A) Both A and R are true and R is the correct explanation of A
Sound waves are longitudinal in nature and light waves are transverse in character. Moreover light wave is electromagnetic in nature. That's why light waves do not need a material medium for its propagation. Moreover sound
Hello candidate,
1. The handle open the door is always provided at the age of a dog because if it is provided at the lock them then it would not be able to generate enough call in order to provide a rotational motion to the door in order to open
Hello Candidate,
In the first question, a particle Executes SHM of amplitude A. It's Velocity will be maximum at the point of maximum displacement which is equal to +-A, velocity will be zero at the equilibrium point. The acceleration of the particle will be maximum at the equilibrium point will
Hi,
11km/s.
Escape speed of a body from Earth's surface is given by: vmin = 2gR. This expression is obtained by conservation of energy and doesn't involve in which direction the body is thrown/projected. So, irrespective of the angle of projection, escape speed of the body from Earth's surface remains
The maximum speed of a car on a level circular road of radius of curvature r, so that it can move without skidding is equal to v= √R* g* cos theta, where theta is angle of elevation. So, the maximum speed is independent of the mass of car.
Given, vec(A) =-2i+2j-k
vec(B )= 3i+6j+2k.
Now A cross B =
| i j k |
| -2 2 -1|
| 3 6 2 |
=> A cross B = i(2*2-[-1*6])-j(-2*2-[-1*3])+k(-2*6-[2*3])
=> A cross B = 10i +j - 18k
I hope this answer helps. All the very best for
Using the third equation of motion, that the square of final velocity is equal to the arithmetic sum of the square of initial velocity and 2 multiplied by the acceleration into the distance.
So, taking the initial velocity is equal to zero the expression becomes v^2= u^2+ 2*alpha*distance.
The basic formula of work done by a force is equal to force into displacement but in vector it F.S cos theta. So if a force and displacement graph is given to you and so to find the work done by the force you need to find the
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