PUC
Question : Directions: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.
Option 1: 236 : 325 : 263
Option 2: 189 : 198 : 819
Option 3: 761 : 617 : 176
Option 4: 416 : 641 : 461
Correct Answer: 236 : 325 : 263
Solution : Let's check each option – First option: 236: 325 : 263; In the second number digits are different from the the first and the second number. Second option: 189: 198 : 819; In all three numbers same digits are repeated. Third
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The 13 digit 'Student Number' issued from PUE Department has to be entered by the candidates who appeared for the 12th PUC exam.
To find your 12th/PUC student/Reg number for the KCET application form in 2024, you'll need to check your 12th/PUC registration documents or reach out to your
Question : If $a^2+b^2+c^2=16$, $x^2+y^2+z^2=25$ and $ax+by+cz=20$, then the value of $\frac{a+b+c}{x+y+z}$ is:
Option 1: $\frac{3}{5}$
Option 2: $\frac{5}{3}$
Option 3: $\frac{4}{5}$
Option 4: $\frac{5}{4}$
Correct Answer: $\frac{4}{5}$
Solution : Given: $a^2+b^2+c^2=16$----(equation 1) $x^2+y^2+z^2=25$-----(equation 2) $ax+by+cz=20$-----(equation 3) Substitute the values of $b=0$ and $c=0$ in the given equation 1, we get, $a^2+0^2+0^2=16$ $⇒a^2=16$ $\therefore a=4$ Substitute the values of $y=0$ and $z=0$ in the given equation 2, we get, $x^2+0^2+0^2=25$ $⇒x^2=25$ $\therefore x=5$ Substitute the
Question : The highest population density in India, according to the 2011 Census, is in ______________.
Option 1: Bihar
Option 2: Union Territory of Chandigarh
Option 3: National Capital Territory of Delhi
Option 4: Madhya Pradesh
Correct Answer: National Capital Territory of Delhi
Solution : The correct option is the National Capital Territory of Delhi.
As of the 2011 Census of India, the National Capital Territory of Delhi had the highest population density among all states and union territories in India. Delhi is a densely
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