Saveetha Engineering College, Chennai
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First get your concepts clear, you can start off with Grammar, learn all the important topics such as Subject-Verb Agreement, Preposition, Noun, Pronoun, Adjective, Adverb, Active & Passive Voice, Narration etc. You can go through Wren and Martin for this, Having a strong foundation on grammmar will enable you
We know that, as per the Equation of Motion,
s = ut + 0.5 a t^2
So, for first 3 sec.,
10 = 3u + 0.5 x a x 9
So, 3u + 4.5a = 10.............. ( 1 )
Now, for next 4 sec.,
25 = 7u + 0.5
Given that the distance is directly proportional to the square of time.
So, d ∝ t^2
So, d = k.t^2
Where, k is the constant of proportionality.
Now from first condition,
d = 78m and t = 7 sec.
So, 78 = k. 7^2
So, k = 1.59 =
Using s = ut + 1/2a(t^2), we can write
100 = 4u + 8a
=> u + 2a = 25 ------(1)
Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write
240 =
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