Saveetha Engineering College, Chennai
Using s = ut + 1/2a(t^2), we can write
100 = 4u + 8a
=> u + 2a = 25 ------(1)
Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write
240 =
Ranked No. 3 - Silicon India ranked SSE 3rd among the Top 10 Emerging Indian Engineering Colleges.
NIRF 43rd rank
Based on the cut-off marks obtained in the higher secondary (10+2) examination or should have passed the higher secondary examination of Vocational stream as prescribed by the Government.
Cutoff for
The minimum qualification required for admission into a diploma course is passing of the Secondary School Leaving Certificate (SSLC)/ tenth standard/equivalent examination, with at least 35 percent in science and maths subjects.
The state board of technical education of most of the states in India conducts entrance tests.
Diploma -
HI aspirant,
S=u+1/2a(2n-1)10=u+1/2a(7)...(1)15=u+1/2a(11)...(2)Subtract eq(1)&(2)a=5/2m/s^2U=5/4m/sAfter next third secondS9=5/4+1/2×5/2(2×9-1)S9=22.5m
hence is the answer. you must use this formula to obtain the answer. with this base formula you can solve n number of questions asked in n number of ways. be clear in concepts
all
Hello,
The sectional cutoff for all the sections for sbi clerk mains is decided from state to state. But is almost same for all the states. I have made a table for sbi mains sectional cutoff for Rajasthan state for previous year. It is expected to be nearly same for
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