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Question : _________ is a market where economic agents can freely exchange their endowments with each other.
Option 1: Market economy
Option 2: Centrally planned economy
Option 3: Aggregate demand based economy
Option 4: Aggregate supply based economy
Correct Answer: Market economy
Solution : A market economy is a system in which privately held companies engage in unregulated competition to set prices and determine production. Market economy is a market where economic agents can freely exchange their endowments which each other.
Question : When Lead nitrate is heated, which of the following gases is produced?
Option 1: Nitrogen oxide
Option 2: Lead dioxide
Option 3: Nitrogen dioxide
Option 4: Lead oxide
Correct Answer: Nitrogen dioxide
Solution : The correct option is Nitrogen dioxide.
When Lead Nitrate (Pb(NO3)2) is heated, it undergoes thermal decomposition. The reaction can be represented as: Pb(NO3)2(s) → PbO(s) + NO2(g) + O2(g)
When Lead
Question : Directions: From the given alternative words, select the word that cannot be formed using the letters of the given word. ADMINISTRATION
Option 1: STRAIN
Option 2: TRADITION
Option 3: SITUATION
Option 4: RATION
Correct Answer: SITUATION
Solution : Given: ADMINISTRATION
Now, let's compare all the option words with the word ADMINISTRATION – First option: STRAIN; All the letters of STRAIN are present in the word ADMINISTRATION. Second option: TRADITION; All the letters of TRADITION are present in the word ADMINISTRATION. Third option: SITUATION;
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I cannot guarantee you that nothing will happen. This can go away unnoticed as well but there is no guarantee about that. Errors in your JEE MAINS application sch as providing incorrect information about your Class 12 school name and address, could potentially impact the verification process during JoSAA
Question : If $α$ is an acute angle, $\tan (4α − 50°) = \cot (50° − α)$, then find the value of $α$ (in degrees).
Option 1: 60
Option 2: 45
Option 3: 30
Option 4: 90
Correct Answer: 30
Solution : $\tan (4α − 50°)$ = $\cot (50° − α)$ = $\tan(90°–(50° − α))$ ⇒ $\tan (4α − 50°)$ = $\tan(90°–(50° − α))$ ⇒ $(4α − 50°) = 90°–(50° − α)$ ⇒ $4α − 50° = 40°+α$ ⇒ $3α = 90°$ ⇒ $α = 30°$ Hence,
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