Hey, hope you are doing well!

I went through the website and due to some technical issue the syllabus link is not working. But I am still adding the link here, please check it time to time if it opens.

MCC syllabus (https://www.mcc.edu.in/images/IQAC/NAAC/Criteria1/M.Sc._Plant_Biology__Plant_Biotechnology.pdf)

Plant biology and botany are same. Both

Hi Veena,

The Hindu Bunts of Karnataka comes under OBC Category in JEE Entrance Examination 2020 or any other exam. They are a forward caste in Karnataka and anywhere else also.

Refer here for more info - https://engineering.careers360.com/articles/jee-main-reservation-criteria

Feel free to ask doubts in the Comment Section.

I hope this

Hi Dear,

Following is list of few private colleges offering BAMS course in Maharashtra:

• Jupiter Ayurved Medical College, Nagpur,
• Ayurved Mahavidyalaya & Seth R. V. Ayurved Hospital, Sion
• BHARATI VIDYAPEETH COLLEGE OF AYURVED - [BVCA]
• DR. DY PATIL COLLEGE OF AYURVED, PUNE

For more visit following link:

https://medicine.careers360.com/colleges/list-of-bams-colleges-in-maharashtra

Best of

Hello student. 60610 rank is a bit high. But since there is a reservation in 2A category, you might have chances to get a seat. Since the competetion is going higher, I suggest you to apply for pother colleges too to be on the safer side. If there is any

hi,

see it would be best if you directly go to the institute and discuss the reasons with the college authority. however what ever the reason, due to covid 19 pandemic its getting quite delay to process the admission related steps and works. however you may also email your concern

Hello dear student,

No it is not mandatory that to get admission for bachelors of fisheries science you have to give Neet or only Neet scores are valid. But yes there are few colleges which are accepting Neet scores for bachelors of fisheries like Kerala University of fisheries and ocean

Generally cutoffs changes every year it depends upon various factors like, difficulty level of the entrance exam, number of students applying for the exam, performance of the students in the exam, etc.

But in general if you consider previous year cutoffs then you can easily get CSE in Reva as

V=0+αt1

t1=V/α

Similarity, t2=V/β

or t1+t2=V/α+V/β

=αβV/(α+β)

Hello!

Let us consider the first statement. The train starts from rest and acquires a speed v. So, initial velocity is 0 and final velocity is v.

We know that for uniform motion,

v = u + at. Here a = α .

Therefore,

v = u + α t

• Dayananda Sagar College Of Engineering - DSCE-B.E. in Electronics and Instrumentation Engineering
• Sir M. Visvesvaraya Institute of Technology-B.E. in Mechanical Engineering
• Bangalore Institute of Technology (BIT)-B.E. in Electronics and Instrumentation Engineering
• AIT -