Srishti Manipal Entrance and Aptitude Test
Hello,
If you want to get a free seat in JNTU, Hyderabad you must belong to SC/ST category with parent's annual income less that 2.5 lakhs or you must secure a rank below 10,000.Candidates who secure rank below 10,000 will get full fee reimbursement irrespective of their categories.
Now, to
Hi Nirmal,
As per your cutoff score and previous year cutoff, the colleges you get as per yor score are:-
Srl Venkateswara College of Engineering ,Kancheepuram
Alagappa Chettair Government College of Engineering and Technology, Sivagangai
Sri Krishna College of Enginering and Technology , Coimbatore
RMK Engineering College, Thiruvallur
Anna University
Hey there
Seeing previous year figures and since you have state quota you have chances of getting aerospace engineering in coimbatore campus of amrita university at 15036 rank in AEEE.
check the link
https://engineering.careers360.com/articles/aeee-cutoff
good luck
Dear Yathish,
You can get into a veterinary college with your rank in KCET as the cut off for KCET is :
Dear aspirent,
As KGEC is a government college, there are seats for obc students and first of all you have to attend the entrance test called WB JEE
And students should score more than 60 percentile and also college provides you scholarships for merit students,
7% seats are reserved for
Hello Aspirant,
According to your percentile your rank would be near about 3.4 Lakhs. On the basis of this rank it is quite difficult to get seat in any of the NIT even with your reservation quota of ST.
I would suggest you to prepare for second attempt of JEE-Main
According to the percentile you have mentioned in the question your son's approximate rank would be near about 85,000 and on the basis of this rank and category it is very difficult to get NIT Hamirpur with any branch. Note that this prediction is based on previous year's
Hi Tejaswini
You got 81.38 percentile in JEE main exam, your rank would be approximately in between 19000 to 21000. Also, you can check your expected rank using the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112680,
Hi dear aspirant, as you above mentioned you want to skip binomial and pnc . Ok , but please first mention which exam are you talking about on the basis of that only we can help you out .
Shashanaka,
This year the eligibility criteria of getting 75+ percentage in+2 board or being in top 20 percentile is no longer required for getting admission in IITs, NITs and CFTIs. You just need to get passing certificate.
Now you have got 60.23 percentile in JEE Main and belong to SC
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